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Digiron [165]
3 years ago
14

Which object has the least momentum? object a: m = 1 kg, v = 100 m/s object b: m = 10 kg, v = 12 m/s object c: m = 0.5 kg, v = 1

000 m/s object d: m = 100 kg, v = 2 m/s?
Physics
1 answer:
nirvana33 [79]3 years ago
8 0
A = 1*100 = 100 Ns
b = 10 * 12 = 120 Ns
c = 0.5*1000 = 500 Ns
d = 100 * 2 = 200 Ns

a has least momentum
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Answer with Explanation:

We are given that

D_1=0.15mGy

D_2=0.22mGy

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Q_2=10

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Using the formula then, we get

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D=0.37mGy

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Topic Gravitational force amd firld strength.. help me please
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F_{1,2} = \dfrac{Gm_1m_2}{x^2}

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where <em>x</em> is measured in m.

The mass <em>m₁</em> is attracted to <em>m₂</em> in one direction, and attracted to <em>m₃</em> in the opposite direction such that <em>m₁</em> in equilibrium. So by Newton's second law, we have

F_{1,2} - F_{1,3} = 0

Solve for <em>x</em> :

\dfrac{Gm_1m_2}{x^2} = \dfrac{Gm_1m_3}{(15-x)^2} \\\\ \dfrac{m_2}{x^2} = \dfrac{m_3}{(15-x)^2} \\\\ \dfrac{(15-x)^2}{x^2} = \dfrac{m_3}{m_2} = \dfrac{60\,\rm kg}{40\,\rm kg} = \dfrac32 \\\\ \left(\dfrac{15-x}x\right)^2 = \dfrac32 \\\\ \left(\dfrac{15}x-1\right)^2 = \dfrac32 \\\\ \dfrac{15}x - 1 = \pm \sqrt{\dfrac32} \\\\ \dfrac{15}x = 1 \pm \sqrt{\dfrac32} \\\\ x = \dfrac{15}{1\pm\sqrt{\dfrac32}}

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3 years ago
A vessel that contains a gas has two pressure gauges attached to it. One contains liquid mercury, and the other an oil such as d
castortr0y [4]

Answer:

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