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Art [367]
3 years ago
11

The equation P^xV^yT^z= constant is Boyle law for what is the values of x,y,z​

Physics
1 answer:
chubhunter [2.5K]3 years ago
3 0

I learned the equation as P•V=k•T .

So x=1, y=1, and z= -1 .

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Osmium (os) is the densest element known (density = 22.57 g/cm3). Calculate the mass in pounds and in kilograms of an os sphere
Rufina [12.5K]

<u>Answer:</u>

    Mass in kg = 39.88

    Mass in pounds = 87.92

<u>Explanation:</u>

   We have the expression for Density, ρ = Mass / Volume, in this case density is given and we need to find mass and volume.

   Volume of a sphere, we have the expression V = \frac{4}{3} \pi r^3, where r is the radius of sphere.

   Radius of sphere, r = Half of diameter = 15/2 = 7.5 cm

   So V = \frac{4}{3}* \pi* 7.5^3 = 1767.15 cm^3

  Mass = Volume *  Density = 1767.15*22.57 = 39884.49 g

    Mass in kg = 39884.49/1000 = 39.88 kg

    Mass in pounds = 39.88*2.205 = 87.92 lb

4 0
3 years ago
The picture shows two different species of mammals that use wings to glide among tree tops. However, scientists theorize that th
AlekseyPX

Answer:

c

Explanation:

6 0
3 years ago
Read 2 more answers
Does a rolling ball on a level floor have PE or KE? Explain.
ANEK [815]
Kinetic energy since if its rolling is already using the stored potential energy that it had before it was given an amount of energy to release it for a given time
8 0
3 years ago
The volume flow rate of blood leaving the heart to circulate throughout the body is about 5 L/min for a person at rest. All this
skelet666 [1.2K]

Answer:

n=2.9\times 10^9

A=1.88\times 10^{-8}\ m^2

Explanation:

Given that

Q= 5 L/min

1 L = 10⁻³ m³/s

1 min = 60 s

Q=0.083 x 10⁻³ m³/s

d= 6 μm

v= 1 mm/s

So the discharge flow through one tube

q = A v

A=\dfrac{\pi}{4}d^2

A=\dfrac{\pi}{4}\times (6\times 10^{-6})^2\ m^2

A=2.8 x 10⁻¹¹ m²

v= 1 x 10⁻³  m/s

q= 2.8 x 10⁻¹⁴  m³/s

Lets take total number of tube is n

Q= n q

n=Q/q

n=\dfrac{0.083\times 10^{-3} }{ 2.8\times 10^{-14}}

n=2.9\times 10^9

Surface  area A

A= π d L

A=\pi \times 6\times 10^{-6}\times 10^{-3}\ m^2

A=1.88\times 10^{-8}\ m^2

7 0
3 years ago
2. An 873 kg dragster accelerates at a rate of 44.6 m/s during a race.
Ira Lisetskai [31]

Answer:

<h3>38,673.9N</h3>

Explanation:

According to newton's second law:

Force = mass * acceleration

Given

Mass = 873kg

acceleration = 44.66m/s²

Magnitude of the force is expressed as;

F = ma

F = 873 * 44.6

F = 38,673.9N

<em>Hence the magnitude of the net force exerted on the dragster during this time is 38,673.9N</em>

8 0
3 years ago
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