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2 years ago

Question 3

Physics

1 answer:

Yuki888 [10]2 years ago

4 0

Answer:

$Power = 2.5kW$

Explanation:

Given

$Mass = 200kg$ -- mass of tub

$Energy = 200,000J$

$Time = 80s$

Required

Determine the amount of power needed

Power is calculated as thus:

$Power = \frac{Energy}{Time}$

Substitute values for Energy and Time

$Power = \frac{200,000J}{80s}$

$Power = 2500W$

Divide by 1000 to convert to kW (kilowatt)

$Power = 2.5kW$

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Most humans would die do to the excess oxyegen

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2 years ago

How much work is needed to lift a 3kg create a vertical displacement of 22m

Ulleksa [173]

I think its W= 647.239J

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2 years ago

a baseball is hit 3 feet above ground level at 100 feet per second and at an angle of 45 with respect to the ground. (g=32 feet/

LiRa [457]

Answer:

hmax=81ft

Explanation:

Maximum height of the object is the highest vertical position along its trajectory.

The vertical velocity is equal to 0 (Vy = 0)

$0=V_{y}-g*t=v_{0}*sin(\alpha)-g*th\\$

we isolate th (needed to reach the maximum height hmax)

$th = \frac{v_{0}*sin(\alpha)}{g}$

The formula describing vertical distance is:

$y = Vy * t-g* t^{2} / 2$

So, given y = hmax and t = th, we can join those two equations together:

$hmax = Vy* th-g*th^{2}/2$

$hmax =Vo^{2}*sin(\alpha )^{2}/(2*g)$

if we launch a projectile from some initial height h all you need to do is add this initial elevation

$hmax =h+Vo^{2}*sin(\alpha)^{2}/(2*g)$

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6 0

3 years ago

The wavelength of yellow sodium light in air is 589 nm.

julsineya [31]

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3 years ago

What is the de Broglie wavelength of an object with a mass of 2.50 kg moving at a speed of 2.70 m/s? (Useful constant: h = 6.63×

xxMikexx [17]

Answer:

9.82 × $10^{-35}$ Hz

Explanation:

De Broglie equation is used to determine the wavelength of a particle (e.g electron) in motion. It is given as:

λ = $\frac{h}{mv}$

where: λ is the required wavelength of the moving electron, h is the Planck's constant, m is the mass of the particle, v is its speed.

Given that: h = 6.63 × $10^{-34}$ Js, m = 2.50 kg, v = 2.70 m/s, the wavelength, λ, can be determined as follows;

λ = $\frac{h}{mv}$

= $\frac{6.63*10^{-34} }{2.5*2.7}$

= $\frac{6.63 * 10^{-34} }{6.75}$

= 9.8222 × $10^{-35}$

The wavelength of the object is 9.82 × $10^{-35}$ Hz.

4 0

3 years ago