Answer:
1. 31 Ω
2. 42 Ω
3. V = IR
4. 4 A
5. 1.37 A
Explanation:
Sorry if I make any mistakes reading your handwriting. If I do, let me know and I'll fix it.
1. "Resistors of 5Ω, 10Ω, and 16Ω are connected in series. Find the total resistance."
The resistance of resistors in series is the sum:
R = R₁ + R₂ + R₃
R = 5Ω + 10Ω + 16Ω
R = 31Ω
2. "The total resistance of two resistors connected in series is 75Ω. The value of one resistor is 33Ω. What is the value of the other one?"
Since they are in series, the total resistance is the sum:
75Ω = 33Ω + R
R = 42Ω
3. "State Ohm's law."
Ohm's law states that a voltage drop across a resistor is equal to the resistance times the current.
V = IR
4. To find the current, we first find the total resistance, then use Ohm's law.
R = 10Ω + 15Ω + 30Ω
R = 55Ω
V = IR
220 V = I × 55Ω
I = 4 A
5. Same steps as before.
R = 1.5Ω + 4Ω + 12Ω
R = 17.5Ω
V = IR
24 V = I × 17.5Ω
I = 1.37 A
Given Information:
Current = I = 61 A
Magnetic field = B = 1.30x10⁻⁴
Required Information:
Radius of wire = r = ?
Answer:
r = 0.093 meters
Step-by-step explanation:
Biot-Savart Law is given by
B = μ₀I/2πr
Where μ₀ is the permeability of free space and it is basically a measure of resistance in the formation of magnetic field.
I is the current flowing through the wire and B is the magnitude of the magnetic field produced.
Re-arranging the above equation to find out the radius of the loop
r = μ₀I/2πB
r = 4πx10⁻⁷*61/2π*1.30x10⁻⁴
r = 0.093 m
Hence, the radius of the loop wire is 0.093 meters.
Answer:
Explanation:
Two aircrft pand qare flyingatthe same speed 300m the diraction along tothe diraction of the veloctiy
Answer:
E = 0.13 J
Explanation:
At resonance condition we have
now if the frequency is double that of resonance condition then we have
now we have
now average power is given as
Now time period is given as
so total energy consumed is given as