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Afina-wow [57]
4 years ago
14

A person will feel weightless whenever?

Physics
2 answers:
mars1129 [50]4 years ago
6 0
There are two ways a person could feel weight less. Either when he is a place with zero gravity(space) or when he is In a free fall
gavmur [86]4 years ago
5 0
When your'e in space you feel weightless blc there's no grsvity in space.
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How can you use a ticker tape timer in describing motion graphically?
Bad White [126]
Ticker Tape analysis is a common way of analyzing the motion of the objects to perform in the physics laboratory. A long tape is attached to a moving object and threaded through a device that places a tick upon the tape at regular intervals of time. This ticker tape can also determine if the object is fast or slow. It can also reveal if the object is moving with a constant velocity or accelerating. The changing velocity and acceleration represented by the changing distance between dots in the ticker tape. And also the constant velocity and therefore no acceleration represent the constant distance between dots.

8 0
3 years ago
A copper wire has a radius of 3.5 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o
denpristay [2]

Answer:

The tensile stress on the wire is 550 MPa.

Explanation:

Given;

Radius of copper wire, R = 3.5 mm

extension of the copper wire, e =  5.0×10⁻³ L

L is the original length of the copper wire,

Young's modulus for copper, Y =  11×10¹⁰Pa.

Young's modulus, Y is given as the ratio of tensile stress to tensile strain, measured in the same unit as Young's modulus.

Y =\frac{Tensile \ stress}{Tensile \ strain} \\\\Tensile \ stress = Y*Tensile \ strain\\\\But, Tensile \ strain = \frac{extension}{original \ Length} = \frac{5.0*10^{-3} L}{L} = 5.0*10^{-3}\\\\Tensile \ stress = 11*10^{10} *5.0*10^{-3} \ = 550*10^6 \ Pa

Therefore, the tensile stress on the wire is 550 MPa.

8 0
3 years ago
This is for physical science. Can someone help me?
Radda [10]
A. 320 g
B. 160 g
C. 80 g
D. 40 g
6 0
3 years ago
Read 2 more answers
A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
Marrrta [24]

Answer:

h = 2.64 meters      

Explanation:

It is given that,

Mass of one ball, m_1=3\ kg

Speed of the first ball, v_1=20\ m/s (upward)

Mass of the other ball, m_2=2\ kg

Speed of the other ball, v_2=-12\ m/s (downward)

We know that in an inelastic collision, after the collision, both objects move with one common speed. Let it is given by V. Using the conservation of momentum to find it as :

V=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}

V=\dfrac{3\times 20+2\times (-12)}{3+2}

V = 7.2 m/s

Let h is the height reached by the combined balls of putty rise above the collision point. Using the conservation of energy as :

mgh=\dfrac{1}{2}mV^2

h=\dfrac{V^2}{2g}

h=\dfrac{7.2^2}{2\times 9.8}

h = 2.64 meters

So, the height reached by the combined mass is 2.64 meters. Hence, this is the required solution.

5 0
3 years ago
Because insects are living and moving, what investigator's challenges in collecting insect evidence?
Mama L [17]

Answer:i dont know

Explanation:

8 0
3 years ago
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