Question

Solid potassium chlorate (kclo3) decomposes into potassium chloride and oxygen gas when heated. how many moles of oxygen form when 54.3 g completely decomposes?

Answer 1

0.6645 moles of oxygen O₂  form when 54.3 g solid potassium chlorate KClO₃ completely decomposes

Further explanation

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

Reactions that occur:

2KClO₃ ⇒ 2KCl + 3O₂

We determine the KClO₃ mole to determine the O₂ mole

M KClO₃ = 1. K + 1. Cl + 3. O

M KClO₃ = 1. 39 + 1. 35.5 + 3. 16

M KClO₃ = 39 + 35.5 + 48

M KClO₃ = 122.5

$\displaystyle mole\:KClO_3=\frac{mass}{molar\:mass}$

$\displaystyle mole=\frac{54.3}{122.5}=0.443\:mole$

From the reaction equation, the mole ratio

KClO₃ : O₂  = 2 : 3

then :

$\displaystyle mole\:O_2=\frac{3}{2}\times 0.443\\\\mole\:O_2=\boxed{\bold{0.6645}}$

Learn more  

The mass of one mole of raindrops  

brainly.com/question/5233234  

moles of NaOH  

brainly.com/question/4283309  

moles of water you can produce  

brainly.com/question/1405182  

Keywords: mole, oxygen, potassium chlorate, decomposes,potassium chloride

Answer 2

Answer:

• 0.665 mol of O₂.

Explanation:

1. Molecular chemical equation:

• 2 KClO₃(s) → 2 KCl(s) + 3 O₂(g)

2. Mole ratios:

• 2 mol KClO₃ : 2 mol KCl : 3 mol O₂

3. Number of moles of KClO₃

• Number of moles = mass in grams / molar mass

• Molar mass of KClO₃ = 122.55 g/mol

• Number of moles of KClO₃ = 54.3 g / 122.5 g/mol ≈ 0.44308 mol

3. Number of moles of O₂

As per the theoretical mole ratio 2 mol of KClO₃ produce 3 mol of O₂, then set up a proportion to determine how many  moles of O₂ will be produced from 0.44038 mol of KClO₃.

• 3 mol O₂ / 2 mol KClO₃ = x / 0.44038 mol KClO₃

• x = (3 / 2) × 0.44308 mol O₂ = 0.6646 mol O₂

Round to 3 significant figures: 0.665 mol of O₂ ← answer