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bezimeni [28]
3 years ago
11

How many ml of 0.213-M Na3PO4 are required to deliver 66.4 mmol Na1+ ions?

Chemistry
1 answer:
bezimeni [28]3 years ago
7 0

Given :

Molarity of Na_3PO_4 , M = 0.213 M .

To Find :

How many ml of 0.213 M of Na_3PO_4 are required to deliver 66.4 mmol Na^+.

Solution :

Volume required  :

V=[\text{ 66.4 mmol of }Na^+] + [\dfrac{\text{1 mm of }Na_3PO_4}{\text{3 mmol of }Na^+}]+[\dfrac{\text{1 ml }Na_3PO_4}{\text{0.213 mmol of }Na_3PO_4}]

So ,

V=\dfrac{66.4}{3\times 0.213}\ ml\\\\V=103.91\ ml

Therefore , volume of Na_3PO_4 required is 103.91 ml .

Hence , this is the required solution .

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