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Tems11 [23]
3 years ago
11

11 A student combined 1.2 g of H2 gas and 5.4 g of He gas in a 2.5 L closed container. What was the pressure exerted by the H2 g

as if the mixture was at 22°C? (R = 0.08206 L · atm/mol · K)
36 atm


0.43 atm


12 atm


5.8 atm
Chemistry
2 answers:
blagie [28]3 years ago
7 0
The correct answer is 5.8 atm.
AveGali [126]3 years ago
3 0

Answer:

5.8 atm is correct, just did it

Explanation:

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The solubility of acetanilide in hot water (5.5 g/100 ml at 100∘C) is not very great, and its solubility in cold water (0.53 g/
Olin [163]

Answer:

89.4%

Explanation:

Initially, there is 5.0 of the acetanilide in 100 mL of water, then the solution is chilled at 0ºC. The solubility represents the amount that the solvent (water) can dissolve of the solute (acetanilide). So, at 0ºC, 100 mL of water can dissolve till 0.53 g of the compound, the rest will precipitate and will be recovered.

So, the mass that is recovered is 5.0 - 0.53 = 4.47 g

The percent recovery is:

(4.47/5)x100% = 89.4%

8 0
3 years ago
Determine the number of significant figures in 478 cm​
Grace [21]

Answer:

There are 3 significant figures on this one.

3 0
3 years ago
What is the edge length of a face-centered cubic unit cell that is made of of atoms, each with a radius of 154 pm
gladu [14]

Answer:

The edge length of a face-centered cubic unit cell is 435.6 pm.

Explanation:

In a face-centered cubic unit cell, each of the eight corners is occupied by one atom and each of the six faces is occupied by a single atom.

Hence, the number of atoms in an FCC unit cell is:

8*\frac{1}{8} + 6*\frac{1}{2} = 4 atoms

In a face-centered cubic unit cell, to find the edge length we need to use Pythagorean Theorem:

a^{2} + a^{2} = (4R)^{2}     (1)

Where:

a: is the edge length

R: is the radius of each atom = 154 pm      

By solving equation (1) for "a" we have:

a = 2R\sqrt{2} = 2*154 pm*\sqrt{2} = 435.6 pm    

Therefore, the edge length of a face-centered cubic unit cell is 435.6 pm.   

I hope it helps you!

7 0
4 years ago
How many moles of KClO3 reacted if 9 moles of O2 were produced in this reaction: 2KClO3 → 2KCl + 3O2
kherson [118]
2 mol KClO₃ - 3 mol O₂
x mol KClO₃ - 9 mol O₂

x=9*2/3= 6 mol
3 0
3 years ago
Why does knowing the mass of an object not help you identify what material the object is made from?
jeka57 [31]
Because mass is not always the same for objects made from the same material. Just because an object has the same mass as another doesn’t mean they are the same material.
4 0
4 years ago
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