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Tems11 [23]
3 years ago
11

11 A student combined 1.2 g of H2 gas and 5.4 g of He gas in a 2.5 L closed container. What was the pressure exerted by the H2 g

as if the mixture was at 22°C? (R = 0.08206 L · atm/mol · K)
36 atm


0.43 atm


12 atm


5.8 atm
Chemistry
2 answers:
blagie [28]3 years ago
7 0
The correct answer is 5.8 atm.
AveGali [126]3 years ago
3 0

Answer:

5.8 atm is correct, just did it

Explanation:

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Question 12 of 32
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Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).
muminat

Hello!

Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).

We have the following data:

m (mass) = ? 

n (number of moles) = 5.20 moles

MM (Molar mass of C6H12) ≈ 84.2 g/mol

Now, let's find the mass, knowing that:

n = \dfrac{m}{MM}

5.20\:\:\diagup\!\!\!\!\!\!\!mol = \dfrac{m}{84.2\:g/\diagup\!\!\!\!\!\!\!mol}

m = 5.20*84.2

\boxed{\boxed{m = 437.84\:g}}\end{array}}\qquad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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Rom4ik [11]

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4 0
3 years ago
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