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ELEN [110]
3 years ago
5

The series in the He spectrum that corresponds to the set of transitions where the electron falls from a higher level to the nf

= 4 state is called the Pickering series, an important series in solar astronomy. Calculate the Pickering series wavelength associated with the excited state ni = 6.
Physics
1 answer:
Aleksandr [31]3 years ago
5 0
In this problem, it is necessary to introduce the atomic number Z into the equation. 
E=(2.18×10^-18 J)(Z^2 )|1/(ni^2 )-1/(nf^2 )| E=(2.18×10^-18 J)(2^2 )|1/(6 ^2 )-1/(4 ^2 )|=3.02798×10^-19 J 
Plug the E value calculated into the equation: (wavelength is always positive) 
E=hc/λ 3.02798×10^-19 J=hc/λ λ=6.56×10^-7 m 
656 nm is in the visible spectrum
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Kinetic Energy RE-
tatiyna

Answer:

1) The potential energy, P.E  = 4527.6 J

2) The mass, m = 1.28 kg

3) The height of the bell, h = 4.31 m

4)  The kinetic energy, K.E = 385 J

5) The velocity of the car, V = 22.53 m/s

6) The mass of the car,  m = 17.59 kg

Explanation:

1) The height of the hill, h = 21 m

The carriage with a baby has mass of, m = 22 kg

The potential energy,

                             P.E = mgh

                                   = 22 x 9.8 x 21

                                  = 4527.6 J

2) The height of the platform, h = 20 m

The P.E of the cinder block, P.E = 250 J

The mass,

                                m = P.E / gh

                                     = 250 / (9.8 x 20)

                                    = 1.28 kg

3) The mass of the bell, m = 18 kg

The P.E of the bell, P.E = 760 J

The height of the bell,

                            h = P.E/mg

                               = 760 / 18 x 9.8

                               = 4.31 m

4) The mass of the runner, m = 55 kg

The velocity of the runner, v = 14 m/s

The kinetic energy,

                              K.E = ½ mv²

                                     = ½ x 55 x 14

                                     = 385 J

5)The kinetic energy of the car, K.E = 69,759 J

The mass of the car, m = 275 kg

The velocity of the car,

                                 V = √(2K.E/m)

                                  V = √( 2 x 69759 / 275)

                                      = 22.53 m/s

6) The velocity of the car, v = 38 m/s

The kinetic energy of the car, K.E = 12700 J

The mass of the car,

                                m = 2 K.E/ v²

                                     = 2 x 12700 / 38²      

                                 m = 17.59 kg

8 0
3 years ago
What is kinematics?<br>explain!!~<br><br>thankyou ~​
artcher [175]

Answer:

Kinematics is the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

-the features or properties of motion in an object.

Explanation:

Hope this helps <3

Have a great day!

7 0
2 years ago
Read 2 more answers
You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, it accelerates because t
zepelin [54]

You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, the average force on the jet is due to the catapult is mathematically given as

What is the average force on the jet is due to the catapult?

Generally, the equation for acceleration is mathematically given as

a=\frac{vf^2-vi^2}{2s}\\\\\Therefore\\\\a=\frac{69.29^2-0^2}{2(90}\\\\a=26.673m/s^2

In conclusion, The force

F=m*a

F=15100*26.673

F=40272.3N

F 402 KN

Read more about force

brainly.com/question/13191643

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6 0
2 years ago
When an electron falls from a higher to a lower energy level in an atom, the photon released has a wavelength of 121.6 nm. What
yarga [219]

Answer:

\Delta E=1.64*10^{-18}J

Explanation:

The energy difference between the energy levels involved in the transition of the electron is directly proportional to the frequency of the emitted photon:

\Delta E=h\nu(1)

Where h is the Planck constant. The photon's frequency is inversely proportional to its wavelegth:

\nu=\frac{c}{\lambda}(2)

Here c is the speed of light. Replacing (2) in (1):

\Delta E=\frac{hc}{\lambda}\\\Delta E=\frac{(6.63*10^{-34}J\cdot s)(3*10^8\frac{m}{s})}{121.6*10^{-9}m}\\\Delta E=1.64*10^{-18}J

6 0
3 years ago
On a roller coaster, riders can experience a force of up to 4 g. What is the maximum acceleration of the roller coaster?
yKpoI14uk [10]

m/s^2 is 39.2266

is the answer If thats what you needed


7 0
3 years ago
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