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Doss [256]
3 years ago
11

Convert 75 mL of water to gallons (show work)​

Chemistry
1 answer:
lina2011 [118]3 years ago
4 0

Answer:

\huge\boxed{\sf 75\ mL = 0.02\ gallons}

Explanation:

1 mL = 0.000264 gallons

<em><u>Multiplying both sides by 75</u></em>

75 mL = 0.000264 * 75 gallons

<h2>75 mL = 0.02 gallons</h2>
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Which conversion factor should you use first to calculate the number of grams of co2 produced by the reaction of 50.6 g of ch4 w
Ira Lisetskai [31]
Answer is: <span>1 mol CH</span>₄/<span>16,0 g CH</span>₄.
Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
m(CH₄) = 50,6g.
M(CH₄) = 16g/mol.
n(CH₄) = m(CH₄) ÷ M(CH₄) = 50,6g ÷16g/mol = 3,16mol.
n(CH₄) : n(CO₂) = 1:1.
nCO₂) = 3,16mol.
m(CO₂) = m(CO₂) · m(CO₂) = 3,16mol · 44g/mol = 139,15g.
M - molar mass.
n - amount of substance.
8 0
3 years ago
Sound travel at a velocity of 333 m/s. How long does it take for sound to travel the length of a 100.0 yard football field
Scorpion4ik [409]

Answer:

It takes 0.27 second to travel the distance of  100 yard

Explanation:

We can use the formula ( t = d / s )t = d / s  = 91 m / 333 m/s  = 0.27 s

6 0
3 years ago
Describe and explain how molecules of oxygen behave when the temperature is so low that the oxygen becomes a liquid. ( This is s
marshall27 [118]

Answer/Explanation: Oxygen becomes liquid at -183°C.

Liquid nitrogen has a lower boiling point at −196 °C (77 K) than oxygen's −183 °C (90 K), and vessels containing liquid nitrogen can condense oxygen from air.

8 0
3 years ago
When 0.514 g of biphenyl (c12h10) undergoes comubustion in a bomb calorimeter, the temperature increases from 25.80 °c to 29.40
slava [35]
The  change  in  internal   energy  of the   combustion  of  biphenyl  in  Kj  is  calculated  as follows

  =heat  capacity of  bomb  calorimeter x  delta  T  where  delta T   is  change   in temperature
delta T  = 29.4  -25.8= 3.6 c

= 5.86 kj/c   x  3.6 c =  21.096  kj


7 0
4 years ago
What is the minimum frequency of light required to observe the photoelectric effect on pd
Tems11 [23]

Answer:

1.26 × 10¹⁵ s⁻¹

Explanation:

Work function is the minimum energy required to remove an electron from the surface of metal

energy of the electron = hf - Φ

Φ = work function = hf₀ where f₀  = threshold frequency

f₀ = Φ / h  where h ( Planck constant = 6.626 × 10⁻³⁴ Js)

Φ = 5.22eV = 5.22 × 1 eV  where 1 eV = 1.60217662 × 10⁻¹⁹ J

Φ = 5.22 × 1.60217662 × 10⁻19 J = 8.363362 × 10⁻¹⁹ J

f₀ =  (8.363362 ×10⁻¹⁹  J) / (6.626× 10⁻³⁴ Js) = 1.26 × 10¹⁵ s⁻¹

The frequency must be greater than the 1.26 × 10¹⁵ s⁻¹ to observe the emission

3 0
4 years ago
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