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djverab [1.8K]
3 years ago
7

The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kJ. You may want to re

ference (Pages 381 - 385) Section 9.6 while completing this problem.
Chemistry
1 answer:
aivan3 [116]3 years ago
6 0

This is an incomplete question, here is a complete question.

The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kJ. You may want to reference (Pages 381 - 385) Section 9.6 while completing this problem. If the change in enthalpy is -5074.2 kJ, how much work is done during the combustion? Express the work in kilojoules to three significant figures.

Answer : The work done during the combustion is, 9.9 kJ

Explanation :

Formula used :

\Delta H=\Delta E+w

where,

w = work done = ?

\Delta H = change in enthalpy  = -5074.2 kJ

\Delta E = change in internal energy  = -5084.1 kJ

R = gas constant = 8.314 J/mol.K

Now put all the given values in the above formula, we get:

-5074.2kJ=-5084.1kJ+w

w=9.9kJ

Thus, the work done during the combustion is, 9.9 kJ

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