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ANTONII [103]
3 years ago
6

A water supply agency is planning to add two reservoirs to its system. Water will flow from Reservoir A to Reservoir B via a 10,

000-ft-long, 24-inch diameter steel pipe. The pipe will be installed beneath a road between the two reservoirs. The road crosses over a hill with a summit elevation of 375 ft above MSL. This summit is at a distance of 3000 ft from reservoir A.The elevation of the water surface in reservoir A will vary between 348.0 and 362.0 ft above MSL and the water surface in reservoir B will vary between 244.1 and 255.4 ft above MSL.Assume a temperature of 50°F. Neglect minor losses. Use a Hazen-Williams friction factor of 100 and an equivalent sand grain roughness of 0.060 in. These values are from Table 12.1.1 in the text.(a) Make a sketch that defines the geometry of the problem. Clearly label dimensions.(b) Determine which water level combination will lead to maximum discharge in the pipe and which water level combination will lead to minimum discharge in the pipe. This should be done by analyzing the relevant equations without doing any calculations. Show your work and explain your logic.

Engineering
1 answer:
NikAS [45]3 years ago
3 0

Attached is the solution to the above question.

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List the three parts of an atom in the Bohr Model
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Structure Of The Atom: Our current model of the atom can be broken down into three constituents parts – protons, neutron, and electrons. Each of these parts has an associated charge, with protons carrying a positive charge, electrons having a negative charge, and neutrons possessing no net charge.
7 0
3 years ago
Which of the following would require the filing of an EIS? a. expansion of an airport in a national park b. allowing snowmobiles
alekssr [168]

Answer:

d. All of the above would require an EIS.

Explanation:

A document prepared with the aim of describing the impacts of suggested operations on the environment is an Environmental Impact Statement (EIS). There was a mistake. An Environmental Impact Statement (EIS) is therefore a report describing the environmental effects resulting from a current action. All of the activities above would have an effect on the environment and therefore must fill an EIS

6 0
4 years ago
Which of these is the BEST description of
strojnjashka [21]

Answer:

i would say C but i may be wrong have a great day

Explanation:

3 0
3 years ago
A pipe is insulated such that the outer radius of the insulation is less than the critical radius. Now the insulation is taken o
irina [24]

Answer:

the heat transfer from the pipe will decrease when the insulation is taken off for r₂< r_{cr}

where;

r₂ = outer radius

r_{cr} = critical radius

Explanation:

Note that the critical radius of insulation depends on the thermal conductivity of the insulation k and the external convection heat transfer coefficient h .

r_{cr} =\frac{k}{h}

The rate of heat transfer from the cylinder increases with the addition of insulation for outer radius less than  critical radius (r₂< r_{cr}) 0,  and reaches a maximum when r₂ = r_{cr}, and starts to decrease for r₂< r_{cr}. Thus, insulating the pipe may actually increase the rate of heat transfer from the pipe instead of decreasing it when r₂< r_{cr} .

7 0
3 years ago
There are two types of cellular phones, handheld phones (H) that you carry and mobile phones (M) that are mounted in vehicles. P
nexus9112 [7]

Answer:

A) P(W) = 0.5

B) P(MF) = 0.3

C) P(H) = 0.6

Explanation:

We are told that there are two types of cellular phones which are handheld phones (H) that you carry and mobile phones (M) that are mounted in vehicles.

Also, Phone calls can be classified by the traveling speed of the user as fast (F) or slow (W).

Thus, the sample space is combination of types and classification we are given and it is written as;

S = {HF, HW, MF, MW}

A) Now, phones can either be fast(F) or slow(W). Thus, we can write;

P(F) + P(W) = 1

We are given P(F) = 0.5

Thus;

0.5 + P(W) = 1

P(W) = 1 - 0.5

P(W) = 0.5

B) Now, from the problem statement, a phone call can either be made with a handheld(H) or mobile(M). Thus the sample space partition is {H, M} and we can express as;

P(H ∩ F) + P(M ∩ F) = P(F)

We are given P[F] = 0.5 and P[HF] = 0.2.

P(H ∩ F) is same as P[HF]

Also, P(M ∩ F) is same as P(MF)

Thus;

0.2 + P(MF) = 0.5

P(MF) = 0.5 - 0.2

P(MF) = 0.3

C) Similarly, mobile Phone calls can either be fast or slow. It means the sample space partition is {F, W}

Thus;

P(M) = P(MW) + P(MF)

P(M) = 0.1 + 0.3

P(M) = 0.4

Now, since cellular phones can either be handheld(H) or Mobile(M), then we can say;

P(H) + P(M) = 1

P(H) + 0.4 = 1

P(H) = 1 - 0.4

P(H) = 0.6

5 0
3 years ago
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