Answer:
R= 53.7 Ω
Explanation:
fc= 1/(2πRC)
3000=1/(2π× 1 × 10^-6 × R)
R= 53.7 Ω
Answer:
critical stress required for the propagation is 27.396615 × N/m²
Explanation:
given data
specific surface energy = 0.90 J/m²
modulus of elasticity E = 393 GPa = 393 × N/m²
internal crack length = 0.6 mm
to find out
critical stress required for the propagation
solution
we will apply here critical stress formula for propagation of internal crack
( σc ) = .....................1
here E is modulus of elasticity and γs is specific surface energy and a is half length of crack i.e 0.3 mm = 0.3 × m
so now put value in equation 1 we get
( σc ) =
( σc ) =
( σc ) = 27.396615 × N/m²
so critical stress required for the propagation is 27.396615 × N/m²
A law stating that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.
Hope it helps
Answer:
69.62
Explanation:
The calculation of this question is as below:-
Consumption: 187W
Everyday operates: 17hours
cost of electricity: 0.06 per kWh
so, the annual operating cost
= Consumption ÷ kWh × Everyday operates × cost of electricity × total number of days in a year
Annual operating cost = 187W ÷ 1000 × 17h × 0.06 × 365 days
= 69.62