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ludmilkaskok [199]
3 years ago
15

Technician A says that when using an impact wrench to remove a bolt from the front of an engine's crankshaft, the crankshaft mus

t be held to keep it from turning. Technician B says that when using an impact wrench to remove lug nuts on a raised vehicle, the brakes must be applied. Who is right?
a. Technician A
b. Technician B
c. Both A and B
d. Neither A nor B
Engineering
1 answer:
Lady bird [3.3K]3 years ago
3 0

Answer:

d. Neither A nor B

Explanation:

Mostly for exhaust bolts we use impact wrenches. Impact wrenches are very useful on flywheels because the crank shaft needs to be fixed from rotating. Also impact wrenches are useful on cars for loosening wheel nuts.  The wheels need not to be restrained or the brakes need not to be applied to fiz wheels in position.

You might be interested in
Can a heat engine operating with only one thermal reservoir?
Harlamova29_29 [7]

Answer:

No

Explanation:

Heat engine is a device which operates between two thermal reservoir.One thermal reservoir supply the thermal energy to the heat engine and another thermal reservoir absorb heat rejected by heat engine.These thermal reservoir are infinite amount of heat capacity system.Temperature of thermal reservoir remain constant always.

So we can say that heat engine can not operate by using only one thermal reservoir.

5 0
3 years ago
Find the current in 1 the electrical circuit below
Lesechka [4]

Answer:

  c.  25 μA

Explanation:

The dependent current source means that 31 times i1 will flow through the 6kΩ resistor, effectively increasing its voltage drop to 31 times that which would result from i1 alone. In effect, the 6kΩ resistor behaves in the left-side circuit loop as though it were 31×6kΩ = 186kΩ (with no dependent current source).

Then the current i1 is equivalent to that created by a 5+1 = 6V source through a 54kΩ +186kΩ = 240kΩ circuit impedance.

  (6V)/(240kΩ) = 25 μA

_____

<em>Additional comment</em>

The voltage across the 6kΩ resistor is (186/240)·6V = 4.65V, and the 25 μA current generates a voltage of 30·(25 μA)(1.8kΩ) = 1.35V across the 1.8kΩ resistor. This means the voltage source at the right side of the diagram needs to be at least 4.65 +1.35 = 6.0V in order to support the calculated voltage drops.

3 0
3 years ago
Air is compressed by an adiabatic compressor from 100 kPa and 20°C to 1.8 MPa and 400°C. Air enters the compressor through a 0.1
Tamiku [17]

Answer:

(a) the mass flow rate of air is 5.351 kg/s

(b) the input power required is 2090.786 kW

Explanation:

Given;

initial pressure, P₁ = 100 kPa

initial temperature, T₁ = 20 °C

Final pressure, P₂ = 1.8 MPa

Final temperature, T₂ = 400 °C

Inlet area of the compressor = 0.15 m²

outlet area of compressor = 0.078 m²

velocity of air = 30 m/s

Part (a) mass flow rate of air through the inlet

Mass flow rate = Area x velocity = density x volumetric rate

m = Av = ρV

from ideal gas law, PV = nRT and ρ = m/V

substitute these values in the above equations, we will have;

m = \frac{PAv}{RT}

m = \frac{100000*0.15*30}{287*(20+273)}= 5.351 \ kg/s

Part (b) the required power input

W + m(h_1+\frac{v_1{^2}}{2}) = mh_2

where;

W is the input power

m is the mass flow rate

h₁ is the initial enthalpy

h₂ is the final enthalpy

initial and final enthalpy are obtained from steam table using interpolation;

h₁ = 293.166 kJ

h₂ = 684.344 kJ

W + m(h_1+\frac{v_1{^2}}{2}) = mh_2\\\\W = mh_2 - m(h_1+\frac{v_1{^2}}{2})\\\\W = 5.351 ( 684.344) - 5.351 (293.166 + \frac{30^2}{2000}) \\\\W = 3661.925 \ kW -1571.139 \ kW\\\\W = 2090.786 \ kW

7 0
3 years ago
Read 2 more answers
Where is the specific machine information concerning lubrication/maintenance found?
artcher [175]

The specific machine information concerning lubrication/maintenance found is Preventative Maintenance Manual.

<u>Explanation:</u>

Specific machine information concerning lubrication/maintenance is required for a long life term of the machine as well as for better availability and great profit. The specific machine information concerning lubrication/maintenance found is Preventative Maintenance Manual.

This manual helps the machines to have better maintenance and also prevents the danger that they might occur anytime.

This maintenance helps the equipment process day to day without any issues. Everything is kept under schedule, the past inspections are recorded, and every maintenance scheduled in future are followed under certain time and checks on the service reports.

8 0
3 years ago
Problem 1: Energy from Flow. Before the advent of the steam-powered engine, most mechanical processes were driven by extracting
tester [92]

Answer:

Diameter will be 27394.76 m

Explanation:

Power P = 0.5 kW = 500 W

Time t required for grinding = 1 hr = 3600 sec

Energy required E = P x t

E = 500 x 3600 = 1800000 J

Flow rate of water Q = 400 ltr/min

We convert to m3/sec

400 ltr/min = 400/(1000 x 60) m3/ses

Q = 0.0067 m3/sec

Energy provided by flow will be

E = pgQd

Where p = density of water = 1000 kg/m3

g = acceleration due to gravity 9.81 m/s2

d = diameter of wheel.

Equating both energy, we have,

1800000 = 1000 x 9.81 x 0.0067 x d

1800000 = 65.73d

d = 1800000/65.73

d = 27394.76 m

8 0
3 years ago
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