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ladessa [460]
3 years ago
7

1- A square-wave inverter has a dc source of 96 V and an output frequency of 60 Hz. The load is a series RL load with R = 5 Ohm

and L = 100 mH. Determine (a) Minimum and maximum Current (b) an expression for load current, (c) Amplitudes of the Fourier series terms (1,3,5,7,9) for the square wave load voltage (d) Amplitudes of the Fourier series terms (1,3,5,7,9) for the load current.
Engineering
1 answer:
Helen [10]3 years ago
3 0

Answer:

D

Explanation:A circuit is equivalent to another when the output voltage is equal to each other. This is so because a circuit may have a higher voltage source and lesser load or a lower voltage source and higher load,so we can only say they are equal If the output is similar

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Select the statement that is false.
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List the main activities of exploration??
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3 0
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An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500
Assoli18 [71]

Answer: The exit temperature of the gas in deg C is 32^{o}C.

Explanation:

The given data is as follows.

C_{p} = 1000 J/kg K,   R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)

P_{1} = 100 kPa,     V_{1} = 15 m^{3}/s

T_{1} = 27^{o}C = (27 + 273) K = 300 K

We know that for an ideal gas the mass flow rate will be calculated as follows.

     P_{1}V_{1} = mRT_{1}

or,         m = \frac{P_{1}V_{1}}{RT_{1}}

                = \frac{100 \times 15}{0.5 \times 300}  

                = 10 kg/s

Now, according to the steady flow energy equation:

mh_{1} + Q = mh_{2} + W

h_{1} + \frac{Q}{m} = h_{2} + \frac{W}{m}

C_{p}T_{1} - \frac{80}{10} = C_{p}T_{2} - \frac{130}{10}

(T_{2} - T_{1})C_{p} = \frac{130 - 80}{10}

(T_{2} - T_{1}) = 5 K

T_{2} = 5 K + 300 K

T_{2} = 305 K

           = (305 K - 273 K)

           = 32^{o}C

Therefore, we can conclude that the exit temperature of the gas in deg C is 32^{o}C.

8 0
3 years ago
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