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ladessa [460]
3 years ago
7

1- A square-wave inverter has a dc source of 96 V and an output frequency of 60 Hz. The load is a series RL load with R = 5 Ohm

and L = 100 mH. Determine (a) Minimum and maximum Current (b) an expression for load current, (c) Amplitudes of the Fourier series terms (1,3,5,7,9) for the square wave load voltage (d) Amplitudes of the Fourier series terms (1,3,5,7,9) for the load current.
Engineering
1 answer:
Helen [10]3 years ago
3 0

Answer:

D

Explanation:A circuit is equivalent to another when the output voltage is equal to each other. This is so because a circuit may have a higher voltage source and lesser load or a lower voltage source and higher load,so we can only say they are equal If the output is similar

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As resistors are added in series to a circuit, the total resistance will
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The equivalent of the resistance connected in the series will be Req=R₁+R₂+R₃.

<h3>
What is resistance?</h3>

Resistance is the obstruction offered whenever the current is flowing through the circuit.

So the equivalent resistance is when three resistances are connected in series. When the resistances are connected in series then the voltage is different and the current remain same in each resistance.

V eq    =    V₁    +    V₂    +    V₃

IReq    =    IR₁    +    IR₂   +    IR₃

Req    =    R₁    +    R₂   +    R₃

Therefore the equivalent of the resistance connected in the series will be Req=R₁+R₂+R₃.

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8 0
2 years ago
An inventor claims to have invented a heat engine that operates between the temperatures of 627°C and 27°C with a thermal effici
Oksana_A [137]

Answer Explanation:

the efficiency of the the engine is given by=1-\frac{T_2}{T_1}

where T₂= lower temperature

           T₁= Higher temperature

we have given efficiency =70%

lower temperature T₂=27°C=273+27=300K

higher temperature T₁=627°C=273+627=900K

efficiency=1-\frac{T_2}{T_1}

                =1-\frac{300}{900}

                 =1-0.3333

                 =0.6666

                 =66%

66% is less than 70% so so inventor claim is wrong

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3 years ago
A PLL is set up so that its VCO free-runs at 8.9 MHz. The VCO does not change frequency unless its input is within plus or minus
pickupchik [31]
It’s A 75khz because it’s plus or minus so if u add it would be too much
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I have a question.What does DIY mean?
alexdok [17]

Answer: It means "Do it yourself".

Explanation: You're welcome!

6 0
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An automobile weighing 2500 lbf increases its gravitational potential energy by a magnitude of 2.25 × 104 Btu in going from an e
Mila [183]

Answer:

The elevation at the high point of the road is 12186.5 in ft.

Explanation:

The automobile weight is 2500 lbf.

The automobile increases its gravitational potential energy in 2.25 * 10^4 BTU. It means the mobile has increased its elevation.

The initial elevation is of 5183 ft.  

The first step is to convert Btu of potential energy to adequate units to work with data previously presented.

British Thermal Unit - 1 BTU = 778.17  lbf*ft

2.25 * 10^4 BTU (\frac{778.17 lbf*ft}{1BTU} ) = 1.75 * 10^7 lbf * ft

Now we have the gravitational potential energy in lbf*ft. Weight of the mobile is in lbf and the elevation is in ft. We can evaluate the expression for gravitational potential energy as follows:  

Ep = m*g*(h_2 - h_1)\\ W = m*g  

Where m is the mass of the automobile, g is the gravity, W is the weight of the automobile showed in the problem.  

h_2 is the final elevation and h_1 is the initial elevation.

Replacing W in the Ep equation

Ep = W*(h_2 -h_1)\\(h_2 -h_1) = \frac{Ep}{W} \\h_2 = h_1 + \frac{Ep}{W}\\\\

Finally, the next step is to replace the variables of the problem.  

h_2 = 5183 ft + \frac{1.75 * 10^7 lbf*ft}{2500 lbf}\\h_2 = 5183 ft + 70003.5 ft\\h_2 = 12186.5 ft

The elevation at the high point of the road is 12186.5 in ft.  

3 0
3 years ago
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