Chemical bond where electrons are shared and usually formed between two nonmetals

Energy Levels: An ionized atom having Z protons has had all but one of its electrons removed. If E is the total energy of the gr

S_A_V [24]

Explanation:

Formula for energy value is as follows.

E = $\frac{-E_{0}}{n^{2}}$

where, $E_{0}$ = 13.6

n = number of shell

So, at ground state energy of hydrogen atom will be as follows.

E = $\frac{-E_{0}}{n^{2}}$

= $\frac{-13.6}{(1)^{2}}$

= -13.6

Hence, for an ionized atom value of energy will be as follows.

E' = $-13.6 \times Z^{2}$

or, E' = $E \times Z^{2}$

Thus, we can conclude that total energy of the remaining electron in the ionized atom is $E \times Z^{2}$ .

7 0

3 years ago

Determine the mass of water produced from 50g hydrochloric acid and

Alenkinab [10]

Answer:

24.7 grams H₂O

Explanation:

To find the mass of water, you should (1) convert from grams HCl to moles (via molar mass from periodic table), then (2) convert from moles HCl to moles H₂O (via mole-to-mole ratio from equation), and then (3) convert from moles H₂O to grams (via molar mass from periodic table).

1 HCl + KOH --> 1 H₂O + KCl

Molar Mass (HCl): 1.008 g/mol + 35.45 g/mol
Molar Mass (HCl): 36.458 g/mol

Molar Mass (H₂O): 2(1.008 g/mol) + 16.00 g/mol
Molar Mass (H₂O): 18.016 g/mol

50 g HCl 1 mole HCl 1 mole H₂O 18.016 g
-------------- x ------------------ x ------------------- x ------------------- = 24.7 g H₂O
36.458 g 1 mole HCl 1 mole H₂O

3 0

2 years ago

Please help me!!!!!!!!!!

ladessa [460]

Answer:

i can't see the image so sorry

Explanation:

i couldnt see the imagee

5 0

3 years ago

Which type of matter tends to become LESS soluble in water as the temperature rises? *

Kisachek [45]

B.liquids thanks have a great day

8 0

3 years ago

Draw the structures of all monofluoro derivatives of methylcyclopentane, c6h11f, which have the fluorine on a primary carbon.

STatiana [176]

Answer: There are 4 monofluoro derivatives of methylcyclopentane. Only 1 derivative has flourine atom attached to a primary carbon.

Explanation: The compound methylcyclopentane has 1-primary carbon, 4- secondary carbons and 1-tertiary carbon.

1) Primary carbon (1°): In this the carbon atom is attached directly to only one carbon atom.

2) Secondary carbon (2°): In this the carbon is attached directly to two carbon atoms.

3) Tertiary Carbon (3°): In this the carbon is attached directly to three carbon atoms.

The monofluoro derivatives are shown in the image below.

Structure B is the only derivative which has fluorine attached to primary carbon atom.

3 0

3 years ago