Answer:
Explanation:
the chemical breakdown of a substance by bacteria, yeasts, or other microorganisms, typically involving effervescence and the giving off of heat.
avogadros law states that under constant temp n pressure, volume of a gas is directly proportional to amount of gas
amount of gas1 = 352millimoles
amount of gas2 = 352+100 = 452millimoles
new vol = old vol x 452/352 = 25.2 x 452/352
= 32.4 mL
Answer:
A. stored energy
Explanation:
potential energy is stored energy.
kinetic energy is the energy of motion
If a metal is less reactive than carbon, it can be extracted from its oxide by heating with carbon. The carbon displaces the metal from the compound, and removes the oxygen from the oxide. This leaves the metal.
A cylindrical weight with a mass of 3 kg is dropped onto the piston from a height of 10 m. The entropy of the gas is 1.18 J/K and the change in the entropy of the environment is -1.18 J/K.
A cylindrical weight with a mass (m) of 3 kg is dropped, that is, its initial velocity (u) is 0 m/s and travels 10 m (s). Assuming the acceleration (a) is that of gravity (9.8 m/s²). We can calculate the velocity (v) of the weight in the instant prior to the collision with the piston using the following kinematic equation.
![v^{2} = u^{2} + 2as = 2 (9.8 m/s^{2} ) (10m) \\\\v = 14 m/s](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20u%5E%7B2%7D%20%2B%202as%20%3D%202%20%289.8%20m%2Fs%5E%7B2%7D%20%29%20%2810m%29%20%5C%5C%5C%5Cv%20%3D%2014%20m%2Fs)
The object with a mass of 3 kg collides with the piston at 14 m/s, The kinetic energy (K) of the object at that moment is:
![K = \frac{1}{2} m v^{2} = \frac{1}{2} (3kg) (14m/s)^{2} = 294 J](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20m%20v%5E%7B2%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%283kg%29%20%2814m%2Fs%29%5E%7B2%7D%20%3D%20294%20J)
The kinetic energy of the weight is completely converted into heat transferred into the gas cylinder. Thus, Q = 294 J.
Given all the process is at 250 K (T), we can calculate the change of entropy of the gas using the following expression.
![\Delta S_{gas} = \frac{Q}{T} = \frac{294 J}{250K} = 1.18 J/K](https://tex.z-dn.net/?f=%5CDelta%20S_%7Bgas%7D%20%3D%20%5Cfrac%7BQ%7D%7BT%7D%20%3D%20%5Cfrac%7B294%20J%7D%7B250K%7D%20%3D%201.18%20J%2FK)
The change in the entropy of the environment, has the same value but opposite sign than the change in the entropy of the gas. Thus, ![\Delta S_{env} = -1.18 J/K](https://tex.z-dn.net/?f=%5CDelta%20S_%7Benv%7D%20%3D%20-1.18%20J%2FK)
A cylindrical weight with a mass of 3 kg is dropped onto the piston from a height of 10 m. The entropy of the gas is 1.18 J/K and the change in the entropy of the environment is -1.18 J/K.
Learn more: brainly.com/question/22655760