All gases share common physical properties. Like liquids, gases freely flow to fill the container they are in.
Hope this helps.
Answer:
13.4g
Explanation:
we know that:
1 mole = 6.02 × 10²³ atoms
make the unknown number of moles = x
x = 7.1 × 10²² atoms
putting them both together:
1 mole = 6.02 × 10²³ atoms
x = 7.1 × 10²² atoms
Cross multiply:
6.02 × 10²³ x = 7.1 × 10²²
divide both sides by 6.02 × 10²³
we now have the number of moles of Al₂CO₃
to calculate the grams (mass):
add up all of the atomic masses of Al₂CO₃ to calculate relative formula mass:
(27 × 2) + 12 + (16 × 3) = 114
the grams (mass) of Al₂CO₃:
Answer:
A
Explanation:
Since macroscopic means visible to the naked eye without a microscope it would be A. This is because we can see active phase changes in real time without any magnification like water boiling or ice melting.
First convert the amount of grams you have of each substance to moles. Find your limiting reactant by calculating how many grams are needed to complete this reaction. If done correctly, you would see that we need .226 moles of Potassium to complete this reaction. However, we only have .118 moles of Potassium, so K must be our limiting reactant. Then use the moles of K to find out how many moles of K^2S are made. Then convert the amount of moles of K^2S to grams and you should get 10.3 g K^2S
Answer:
6.61 × 10∧-29 m³
Explanation:
Given data:
Atomic radius= 143 pm = 143 × 10∧-12 m
volume = ?
Formula:
r = a/2√2
143 × 10∧-12 m = a/ 2√2
a= 143 × 10∧-12 m × 2√2
a= 404.4 × 10∧-12 m
where a is edge length, so we can calculate the volume by using following formula:
volume= a³
V= (404.4 × 10∧-12 m)³
v= 6.61 × 10∧-29 m³
