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stepladder [879]
3 years ago
14

4 examples of Substances that sublime?

Chemistry
1 answer:
AVprozaik [17]3 years ago
3 0

1. Dry Ice (solid carbon dioxide)

2. Iodine

3. Arsenic

4. Naphthalene

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There are no negative consequences to using nuclear energy.<br><br> true or false
Travka [436]
False..........
it has so many consequences

7 0
3 years ago
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A standard galvanic cell is constructed so that the overall cell reaction is as given below where M is an unknown metal. 2 Al3+(
jasenka [17]

Answer:

magnesium metal

Explanation:

According to the redox reaction equation, six electrons were transferred hence n=6 and F= Faraday's constant 96500C. ∆G° is given hence E°cell can easily be calculated as follows:

From ∆G°= -nFE°cell

E°cell= -∆G°/nF= -(-411×10^3/96500×6)

E°cell= 0.7098V

But for Al3+(aq)/Al(s) half cell, E°= -1.66V from standard table of reduction potentials.

E°cell= E°cathode- E°anode but Al3+(aq)/Al(s) half cell is the cathode

Hence

E°anode=E°cathode - E°cell

E°anode= -1.66-0.7098= -2.37V

This is the reduction potential of Mg hence the anode material was magnesium metal

5 0
3 years ago
Water vapor is not usually seen.
xeze [42]

Answer:

True

Explanation:

Water vapor is totally invisible.

Without it, there would be no clouds or rain or snow, since all of these require water vapor in order to form. All of the water vapor that evaporates from the surface of the Earth eventually returns as precipitation - rain or snow.

Helped by the <u><em>One</em></u> & <u><em>Only</em></u> <u><em>#QUEEN</em></u> aka <u><em>#DRIPPQUEENMO </em></u>

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5 0
3 years ago
Which of the situations below describes an ethical dilemma related
fredd [130]

Answer: C

Explanation: Pesticides protect our crops, but some studies show that they cause consumers to gain weight:)

8 0
3 years ago
A chemistry student weighs out 0.027 kg of an unknown solid compound X and adds it to 550. mL of distilled water at 30.° C. Afte
QveST [7]

Answer:

1. Yes

2.The solubility of X is 34.55g/L

Explanation:

Solubility of  solute refers to how readily a solute will dissolve in a solvent at a particular temperature. Its the amount of moles or grams required to saturate 1dm^{3} or 1 Litre of water.

From the problem, when the liquid was drained off and amount of X which didn't dissolve was measured, it weighed 0.008kg, this means out of 0.027kg, 0.027-0.008 actually dissolved

= 0.019kg*1000 = 19g.

if 19g is required to saturate 550mL at 30°C,

then\frac{19*1000}{550} will saturate 1L

= 34.545g  will saturate 1Litre

The solubility thus is 34.55g/L

 

5 0
3 years ago
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