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stepladder [879]
3 years ago
14

4 examples of Substances that sublime?

Chemistry
1 answer:
AVprozaik [17]3 years ago
3 0

1. Dry Ice (solid carbon dioxide)

2. Iodine

3. Arsenic

4. Naphthalene

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The nonvolatile, nonelectrolyte testosterone, C19H28O2 (288.40 g/mol), is soluble in benzene C6H6. Calculate the osmotic pressur
dolphi86 [110]

Answer:

3.824 atm

Explanation:

From the ideal gas equation

P = mRT/MW × V

m is mass of testosterone = 12.9 g

R is gas constant = 82.057 cm^3.atm/mol.K

T is temperature of benzene solution = 298 K

MW is molecular weight of testosterone = 288.40 g/mol

V is volume of benzene solution = 286 ml = 286 cm^3

P = 12.9×82.057×298/288.4×286 = 3.824 atm

6 0
3 years ago
Sugar can be converted to carbon dioxide and water by burning in air or by metabolic reactions inside living cells. How are thes
rjkz [21]

Answer:

These reactions are similar because the process is similar and the products are carbon dioxide they are different because the substances are different to outgo these reactions

Explanation:

5 0
3 years ago
Are metallic bonds are found in compounds
Ratling [72]

Answer:

Explanation:

Yes :)

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5 0
3 years ago
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Which statement is true of a reversible reaction at equilibrium?
Vedmedyk [2.9K]

Answer:

D.

The concentration of reactants and the concentration of products are constant.

Explanation:

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Please help quick
Rama09 [41]

Answer:

c = 0.898 J/g.°C

Explanation:

1) Given data:

Mass of water = 23.0 g

Initial temperature = 25.4°C

Final temperature = 42.8° C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Specific heat capacity of water is 4.18 J/g°C

ΔT = 42.8°C - 25.4°C

ΔT = 17.4°C

Q = 23.0 g ×  × 4.18 J/g°C × 17.4°C

Q = 1672.84 j

2) Given data:

Mass of metal = 120.7 g

Initial temperature = 90.5°C

Final temperature = 25.7 ° C

Heat released = 7020 J

Specific heat capacity of metal = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 25.7°C - 90.5°C

ΔT = -64.8°C

7020 J = 120.7 g ×  c ×  -64.8°C

7020 J = -7821.36 g.°C ×  c

c = 7020 J / -7821.36 g.°C

c = 0.898 J/g.°C

Negative sign shows heat is released.

7 0
3 years ago
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