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xz_007 [3.2K]
2 years ago
14

Which substance used during photosynthesis does a plant take in from the soil?

Chemistry
2 answers:
Simora [160]2 years ago
3 0

Answer:

the answer is water

Explanation:

During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil. Within the plant cell, the water is oxidized, meaning it loses electrons, while the carbon dioxide is reduced, meaning it gains electrons. This transforms the water into oxygen and the carbon dioxide into glucose.

Tamiku [17]2 years ago
3 0

Answer: B would be your answer

Explanation:  During photosynthesis, plants take in carbon dioxide (CO 2) and water (H 2 O) from the air and soil. Within the plant cell, the water is oxidized, meaning it loses electrons, while the carbon dioxide is reduced, meaning it gains electrons. This transforms the water into oxygen and the carbon dioxide into glucose. carbon dioxide that carries out from the air and water from the soil are the two main ingredients that a plant leaf requires during photosynthesis. 7th grade Sem 1 13.2.6 Quiz: Chemistry of Life of 5 Which substance used during photosynthesis does a plant take in; Intersectionality is best described as the way personal and social identities combine to influence how a person experiences the world. the impact

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Nonmetals are defined as elements that generally cannot conduct:.
polet [3.4K]

Answer:

Electricity

Explanation:

Nonmetals are defined as elements that generally cannot conduct electricity

3 0
2 years ago
The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abb
Talja [164]

The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abbreviation (w/v) is also common. 262 grams of sucrose are needed to make 655 mL of a 40.0% (w/v) sucrose solution

<h3>Define Solute</h3>

A solute is a material that dissolves in a solution. The amount of solvent present in fluid solutions is greater than the amount of solute. The two most common examples of solutions in daily life are salt and water. Salt is the solute because it dissolves in water.

<h3>forms of ratios for product concentration or yield:-</h3>
  • w/v:- Weight by volume or weight per volume are the terms used. Any solid compound's concentration in a liquid can be calculated using it. It is measurable in gm/ml.
  • Weight by weight ratio is referred to as w/w.It is employed to determine the final yield of the compound obtained from the starting compound. as in —mg/—gm.

       It provides the real yield of the substance or item.

  • Volume/volume. It is used to specify a liquid's composition or percent in a liquid compound.

using w/v we can calculate the weight of sucrose:-

40.0% means 40 g sucrose/ 100 g solution

40.0g sucrose x (655/100)=grams of sucrose

262  grams of sucrose are needed to make 655 mL of a 40.0% (w/v) sucrose solution.

Learn more about Solute here:-

brainly.com/question/14397121

#SPJ4

6 0
1 year ago
Consider this reaction: 2al(s) + 3 cucl2(aq) → 2alcl3(aq) + 3 cu(s) if the concentration of cucl2 drops from 1.000 m to 0.655 m
kirza4 [7]
The average rate of reaction over a given interval can be calculated by taking the difference of concentration on a particular given reactant, and dividing it by the total time. In this case, (1.00 M - 0.655 M)/30 s = 0.0115 M/s, or 0.0115 mol/L-s, and this is the final rate of reaction.
8 0
3 years ago
One method of favoring the formation of an ester is to add excess acetic acid. Suggest another method, involving the right-hand
Inessa [10]

Answer: decrease the temperature of the reaction

Explanation:

CH3COOH + CH3CH2OH ⇌ CH3COOCH2CH3 + H2O

The formation of an ester is an exothermic reaction. Therefore, a decrease in the temperature of the reaction will favour the production of ester.

7 0
2 years ago
A 6.10 M NaCl can be made by adding [x]g of NaCl to a container and making the volume of water up to the 1.00 L line
sergij07 [2.7K]

Answer:

356.484 g.

Explanation:

  • Molarity (M) is defined as the no. of moles of solute (NaCl) dissolved in a 1.0 L of the solvent.

<em>M = (no. of moles of NaCl)/(volume of the solution (L))</em>

M = 6.10 M, volume of the solution = 1.0 L.

∴ No. of moles of NaCl = (M)(volume of the solution (L)) = (6.10 M)(1.0 L) = 6.10 mol.

<em>∵ no. of moles of NaCl = (mass of NaCl)/(molar mass of NaCl)</em>

∴ Mass of NaCl = (no. of moles of NaCl)(molar mass of NaCl) = (6.10 mol)(58.44 g/mol) = 356.484 g.

8 0
3 years ago
Read 2 more answers
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