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erastova [34]
3 years ago
7

Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.7

0 m. It takes the ball 0.60 seconds to complete one full circle. Calculate the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path.
A) 0.0077 N, toward the center of the circle
B) 1.2 N, toward the center of the circle
C) 0.0077 N, along the line tangent to the circle
D) 1.2 N, along the line tangent to the circle
Physics
2 answers:
balu736 [363]3 years ago
5 0

Answer:

1.2 N, toward the center of the circle

Explanation:

It is given that,

Mass of the ball, m = 0.015 kg

The radius of the circle, r = 0.7 m

Time taken by the ball to complete complete circle, t = 0.6 s

We need to find the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path. Here, tension in the string balances the centripetal force so that the ball moves in circular path. So,

T=\dfrac{mv^2}{r}

Since, v=\dfrac{2\pi r}{t}=\dfrac{2\pi \times 0.7}{0.6}=7.33\ m/s

So, T=\dfrac{0.015\times (7.33)^2}{0.7}

T = 1.15 N

or

T = 1.2 N

The direction of centripetal force is toward the center of circle. So, the correct option is (b).

Sophie [7]3 years ago
4 0

Answer:

B) 1.2 N, toward the center of the circle

Explanation:

The circumference of the circle is:

C = 2πr

C = 2π (0.70 m)

C = 4.40 m

So the velocity of the ball is:

v = C/t

v = 4.40 m / 0.60 s

v = 7.33 m/s

Sum of the forces in the radial direction:

∑F = ma

T = m v² / r

T = (0.015 kg) (7.33 m/s)² / (0.70 m)

T = 1.2 N

The tension force is 1.2 N towards the center of the circle.

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Part complete during a collision with a wall, the velocity of a 0.200-kg ball changes from 20.0 m/s toward the wall to 12.0 m/s
Inga [223]

The average force applied to the ball= 106.7 N

Explanation:

Force is given by

f= ΔP/t

ΔP= change in momentum= m Vf- m Vi

m= mass =0.2 kg

Vf= final velocity= 12 m/s

Vi=initial velocity= -20 m/s ( negative because it is going towards the wall which is treated as negative axis)

t= time= 60 ms= 0.06 s

now ΔP= 0.2 [ 12-(-20)]

ΔP=0.2 (32)=6.4 kg m/s

now force F= ΔP/t

F= 6.4/0.06

F=106.7 N

8 0
3 years ago
Why does a metal spoon left on a bowl of hot soup become warm? A) Metal is a conductor. B) Metal is an insulator. C) Metal produ
mr_godi [17]

A: Metal is a conductor it hold the heat

5 0
3 years ago
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What is the smallest sub atomic particle that orbit around the nucleus?
JulijaS [17]
Electron,a negative charged particles revolving around the nucleus.
5 0
3 years ago
A battery is connected to a light bulb in a circuit. There is a current of 2 A in the light bulb.
Georgia [21]

Answer:

Resistance of the light bulb = 1.33 ohm (Approx.)

Explanation:

Given:

Current in electric bulb = 2 Amp

Voltage in battery = 1.5 Volt

Find:

Resistance of the light bulb

Computation:

Resistance = Voltage / Current

Resistance of the light bulb = Voltage in battery / Current in electric bulb

Resistance of the light bulb = 2 / 1.5

Resistance of the light bulb = 1.33 ohm (Approx.)

5 0
2 years ago
a car begins at rest at a stoplight. After the light turns green, the car begins to accelerate 5 m/s squared over the span of 3.
gogolik [260]

Answer: 9m

Explanation:

Our given:

Acceleration- 5m/s^2

Time- 3.6 seconds

Use the equation d = 1/2 • a • t^2

d = 1/2 • 5m/s^2 • 3.6 secs

d = 2.5m/s^2 • 3.6 secs

d = 9m

I hope this is correct

4 0
3 years ago
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