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Andrews [41]
3 years ago
5

What will happen if we put a magnet in cold water

Physics
1 answer:
gayaneshka [121]3 years ago
8 0

Answer:

cold water strengthens the magnetic attractive force.

Explanation:

The molecules within the magnet will move slower because they have less kinetic energy,so there is less vibration within the magnets molecules.

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A woman launches a boat from one shore of a straight river and wants to land at the point directly on the opposite shore. If the
I am Lyosha [343]

Answer:

If she stands on the North side of a river flowing to the East at 5 mph,

she must head towards the SouthWest to arrive on the South side of the river directly across from her starting point and we have

x^2 + 5^2 = 10^2 where x is her speed directly across the river

x = (75)^1/2 = 8.66 mph towards the South

sin theta = 5 / 10 = 1/2

She must angle the boat at 30 deg from straight South

4 0
2 years ago
A 3 kg object is attached to a 1000 N/m spring. The spring is compressed 0.10 m and then the spring launches the object horizont
Viktor [21]

Answer:

1.826m/s

Explanation:

E=1/2*k*(∆L)^2

E=1/2*mV^2

6 0
3 years ago
(HELP!! 10pts) a train travels 75km in 1hr, and then 68km in 2hrs. what is its average speed?
blondinia [14]
Average speed = total distance travelled ÷ total time taken

AS = (75km + 68km) ÷ (1hr + 2hr)

As = 143km ÷ 3hr

AS = 47.66667 km/hr

AS = 47.7 km/hr (3sf)
8 0
3 years ago
Pls help
Arte-miy333 [17]

Answer:

sorry I dont now the answer bro i am so sorry xd ;'(

4 0
3 years ago
An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance o
Minchanka [31]

Answer:

B. 0.16 m

Explanation:

The vertical distance by which the player will miss the target is equal to the vertical distance covered by the dart during its motion.

Since the dart is thrown horizontally, the initial vertical velocity is zero:

v_y = 0

While the horizontal velocity is

v_x = 15 m/s

The horizontal distance covered is

d_x = 2.7 m

Since the dart moves by uniform motion along the horizontal direction, the time it takes for covering this distance is

t=\frac{d_x}{v_x}=\frac{2.7 m}{15 m/s}=0.18 s

along the vertical direction, the motion is a uniformly accelerated motion with constant downward acceleration g=9.8 m/s^2, so the vertical distance covered is given by

d_y = \frac{1}{2}gt^2=\frac{1}{2}(9.8 m/s^)(0.18 s)^2=0.16 m

8 0
4 years ago
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