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zhenek [66]
3 years ago
5

List 3 to 5 ways to reduce friction

Physics
2 answers:
pychu [463]3 years ago
8 0
<span>Make the surfaces smoother. Rough surfaces produce more friction and smooth surfaces reduce friction
Lubrication is another way to make a surface smoother
Make the object more streamlined
Reduce the forces acting on the surfaces
<span>Reduce the contact between the surfaces.</span></span>
svp [43]3 years ago
5 0
<span>1.Make the surfaces smoother. Rough surfaces produce more friction and 2.smooth surfaces reduce friction.

 3.Lubrication is another way to make a surface smoother.

4.Make the object more streamlined

 5.Reduce the forces acting on the surfaces.

<span>6.Reduce the contact between the surfaces.

hope this helps ;)</span></span>
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Why is the work output of a machine never equal to the work input? A. Some work input is used to overcome friction. B. Input dis
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Which acceleration-time graph corresponds to the motion of the car if it moves toward the right, while slowing down at a steady
Bumek [7]

We define acceleration as the rate of change of the velocity

Thus, if you have positive velocity and positive acceleration, your <u>speed increases.</u>

If you have positive velocity and negative acceleration, your speed decreases.

Now you get the idea, we will see that the correct option is graph 1.

We know that the car moves towards the right (let's define this as "the car has positive velocity") and we also know that te car is slowing down constantly (thus the acceleration needs to be negative and constant).

By looking at the graphs, the only one with these properties is graph 1.

If you want to learn more, you can read:

brainly.com/question/12550364

5 0
2 years ago
A package of mass 5 kg sits on an airless asteroid of mass 7.6 × 1020 kg and radius 8.0 × 105 m. We want to launch the package i
Effectus [21]

Answer:

s =  1.7 m

Explanation:

from the question we are given the following:

Mass of package (m) = 5 kg

mass of the asteriod (M) = 7.6 x 10^{20} kg

radius = 8 x 10^5 m

velocity of package (v) = 170 m/s

spring constant (k) = 2.8 N/m

compression (s) = ?

Assuming that no non conservative force is acting on the system here, the initial and final energies of the system will be the same. Therefore  

• Ei = Ef

• Ei = energy in the spring + gravitational potential energy of the system

• Ei = \frac{1}{2}ks^{2} + \frac{GMm}{r}

• Ef = kinetic energy of the object

• Ef = \frac{1}{2}mv^{2}  

• \frac{1}{2}ks^{2} + (-\frac{GMm}{r}) = \frac{1}{2}mv^{2}  

• s = \sqrt{\frac{m}[k}(v^{2}+\frac{2GM}{r})}

s = \sqrt{\frac{5}[2.8 x 10^5}(170^{2}+\frac{2 x 6.67 x10^{-11} x 7.6 x 10^{20}}{8 x 10^5})}

s =  1.7 m

7 0
3 years ago
When popcorn is heated over a flame, the kernel burst open. why does this occur?
Bezzdna [24]
<span>If you faced the situation when  popcorn is heated over a flame and the kernel burst opened the thing which caused that is definitely : the air and water vapor which remain in the kernell have expanded.
Hope that helps.

</span>
4 0
3 years ago
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