Item 10 Find the median, first quartile, third quartile, and interquartile range of the data. 38,55,61,56,46,67,59,75,65,58
jok3333 [9.3K]
I think the median is 58.5, the first quartile is 50.5, the third quartile is 66, and finally, the interquartile range is <span>12.75.</span>
Step-by-step explanation:
you drew already the right things, you have everything.
so, what is the problem ?
the most common form of line equation is
y = ax + b
a is the slope of the line. it is expressed as the ratio
y coordinate change / x coordinate change
when going from one point to the other.
b is the y-intercept (the y value when x = 0).
once we have the slope, we get b by using the coordinates of one of the given points as x and y in the equation and solve for b.
so, for the 2 marked points you showed correctly the differences :
x changes by +8 (from -4 to 4).
y changes by -2 (from 3 to 1).
so the slope is -2/+8 = -1/4
the y-intercept we also see directly in the chart : +2.
The answer is 8 and 13
<span>
y = ax + b
y = 4, x = 1 </span>⇒ 4 = a + b
y = 6, x = 3 ⇒ 6 = 3a + b
Solve the system of equation:
a + b = 4
3a + b = 6
______
b = 4 - a
3a + b = 6
______
3a + 4 - a = 6
2a + 4 = 6
2a = 6 - 4
2a = 2
a = 2/2 = 1
b = 4 - a = 4 - 1 = 3
So, the function rule is: y = x + 3
Thus, if x = 7, then y = 7 + 3 = 10
If x = 10, then y = 10 + 3 = 13
x y
1 4
3 6
4 7
5 8
7 10
10 13
If you graph this, your first point will be at (0,5), as the ramp is at the warehouse door but 5 feet up. The second point is (10,0) as it is touching the ground but it's 10 feet away from the warehouse.
To find slope, you do (y2-y1)/(x2-x1).
When substituting in the variables, you get (0-5)/(10-0), which is -5/10, which is simplified to -1/2. Of course, that is when the warehouse is Quadrant II. If you look at it from another point of view, the slope will be positive so your answer is A) 1/2.
If this was unclear feel free to comment :)
