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alexira [117]
3 years ago
5

A block of mass m is attached to a spring of constant k, which oscillates over a table without friction. Which of the following

assertions is true? Explain why 1. Potential energy of the system is maximum when kinetic energy is also maximum. 2. Potential energy of the system is maximum when block goes through equilibrium position. 3. Kinetic energy of the system is maximum when potential energy is minimum
Physics
1 answer:
Fofino [41]3 years ago
6 0

Answer:

3. Kinetic energy of the system is maximum when potential energy is minimum.

Explanation:

Given that

Mass of block= m

Spring constant =K

Table is friction less.

As we know that in oscillatory motion ,when kinetic energy is maximum then potential energy will become minimum.

At the mean position:

Kinetic energy is maximum.

Potential energy is minimum.

At the extreme position:

Kinetic energy is minimum.

Potential energy is  maximum.

At the mean position velocity of block will be maximum that is why it have maximum kinetic energy and at the extreme position the velocity of block will be minimum that is why it have minimum kinetic energy.

So from above we can say that kinetic energy of the system is maximum when potential energy is minimum.

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Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
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Answer:

final velocity =  0.08585m/s

Explanation:

We are taking train cars as our system. In this system no external force is acting. So we can apply the law of conservation of linear momentum.

The law of conservation of linear momentum states that the total linear momentum of a system remains constant if there is no external force acting on the system. That is total linear momentum before = total linear momentum after

total linear momentum before = linear momentum of first train car + linear momentum of second train car

We know that linear momentum = mv

where,

m = mass

v = velocity

thus,

total linear momentum before = m₁v₁ + m₂v₂

m₁ = mass of first train car = 135,000kg

v₁ = velocity of first train car = 0.305m/s

m₂ = mass of first second car =  100,000kg

v₂ = velocity of second train car =  −0.210m/s

Note: Momentum is a vector. So while adding momentum we should take account of its direction too. Here since second train car is moving in a direction opposite to that of the first one, we have taken its velocity as negative.

total linear momentum before = m₁v₁ + m₂v₂

                                                  = 135,000x0.305 + 100,000x(−0.210)

                                                  = 135,000x0.305 - 100,000x0.210

                                                  = 20,175 kgm/s

Now we have to find total linear momentum after bumping. After the bumping both the train cars will be moving together with a common velocity(say v).

Therefore, total linear momentum after = mv

m = m₁ + m₂ = 135,000 + 100,000 = 235,000

total linear momentum before = total linear momentum after

235,000v = 20,175

v =  \frac{20,175}{235,000}

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8 0
3 years ago
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There are 5 carbon atoms present in the Chemical formula, CHCl_\\{3} .

<h3>What is a chemical formula?</h3>

A chemical formula is used to show the number and type of atoms present in a molecule, using the atomic symbols of the elements and numerical subscripts.

From the chemical formula;

We can deduce that we have the following elements and their corresponding number of atoms in one molecule of the compound;

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In conclusion, from the solution above, we can say that we have 5 atoms of carbon present in 5 molecules of CHCl_3.

Learn more about chemical formula:brainly.com/question/26388921

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