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Nonamiya [84]
3 years ago
15

A solution of calcium chlorate was poured into a sodium fluoride solution. Would you expect a precipitate to form if 255.0 mL of

the calcium chlorate solution (2.0x10-5 M) was mixed with 300.0 mL of a 2.5x10-3 M sodium fluoride solution? A. No, because Qsp < Ksp for calcium fluoride B. Yes, because Qsp < Ksp for calcium fluoride C. Yes, because Qsp = Ksp for sodium chlorate D. Yes, because Qsp = Ksp for calcium fluoride E. No, because Qsp = Ksp for sodium chlorate F. No, because Qsp < Ksp for sodium chlorate G. No, because Qsp > Ksp for calcium fluoride H. No, because Qsp > Ksp for sodium chlorate I. Yes, because Qsp < Ksp for sodium chlorate J. No, because Qsp = Ksp for calcium fluoride K. Yes, because Qsp > Ksp for sodium chlorate L. Yes, because Qsp > Ksp for calcium fluoride

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

A) No , because Qsp<Ksp for calcium fluoride.

Check attachment for calculation

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GaryK [48]

Answer:

234

Explanation:

8 0
2 years ago
The temperature of a gas is 30 degrees Celsius and its pressure is 760 torr. If the temperature originally
erastova [34]
T₁ = 40°C + 273.15 = 313.15 Kelvin T₂ = 30°C + 273.15 = 303.15 Kelvin

Solving Gay-Lussac's Law for P₁ we get:
P₁ = P₂ • T₁ ÷ T₂ P₁ = 760 torr • 313.15 K ÷ 303.15 K P₁ = 785.07 torr

Using the calculator, we click on the P1 button.
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3 years ago
name seven elements that have names and symbols that do not start with the same letter (include the symbol after the name)
viktelen [127]

Answer:

ok will do

Explanation:

5 0
3 years ago
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What is the answer for this 7th grade science
Vaselesa [24]
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5 0
3 years ago
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50g nitrous oxide combines with 50g oxygen form dinitrogen tetroxide according to the balanced equation below.
photoshop1234 [79]

Limiting reactant : O₂

Mass of  N₂O₄ produced = 95.83 g

<h3>Further explanation</h3>

Given

50g nitrous oxide

50g oxygen

Reaction

2N20 + 302 - 2N204

Required

Limiting reactant

mass of N204 produced

Solution

mol N₂O :

\tt =\dfrac{50}{44}=1.136

mol O₂ :

\tt =\dfrac{50}{32}=1.5625

2N₂O+3O₂⇒ 2N₂O₄

ICE method

1.136    1.5625

1.0416  1.5625    1.0416

0.0944    0          1.0416

Limiting reactant : Oxygen-O₂

Mass N₂O₄(MW=92 g/mol) :

\tt =mol\times MW=1.0416\times 92=95.83~g

7 0
3 years ago
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