A negatively charged particle has too many __

The total mass of the atmosphere is about 5.00 x 1018 kg. How many moles each of air, O2, and CO2 are present in the atmosphere?

n200080 [17]

Answer: The moles of oxygen and carbon dioxide in air is $3.63\times 10^{19}mol$ and $7.18\times 10^{16}mol$ respectively

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of atmosphere = $5.00\times 10^{18}kg=5.00\times 10^{21}g$

Average molar mass of atmosphere = 28.96 g/mol

Putting values in above equation, we get:

$\text{Moles of atmosphere}=\frac{5.00\times 10^{21}g}{28.96g/mol}=1.73\times 10^{20}mol$

We know that:

Percent of oxygen in air = 21 %

Percent of carbon dioxide in air = 0.0415 %

Moles of oxygen in air = $\frac{21}{100}\times 1.73\times 10^{20}=3.63\times 10^{19}mol$

Moles of carbon dioxide in air = $\frac{0.0415}{100}\times 1.73\times 10^{20}=7.18\times 10^{16}mol$

Hence, the moles of oxygen and carbon dioxide in air is $3.63\times 10^{19}mol$ and $7.18\times 10^{16}mol$ respectively

6 0

3 years ago

Can someone please help me on the second quick Check!!!!

alexgriva [62]

#1 fossils paragraph 2

8 0

3 years ago

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A reaction contains two reactants, A and B. If A is doubled, there will be a greater number of effective collisions between reac

svlad2 [7]

True true true true true

4 0

3 years ago

A. If both Assertion & Reason are true and the reason is the correct explanation of the assertion. B. If both Assertion &amp

Neporo4naja [7]

Answer:

C. If Assertion is true statement but Reason is false.

Explanation:

The burning of magnesium in air produces magnesium oxide as shown by the equation;

2Mg(s) + O2(g) -----> 2MgO(s)

The magnesium oxide solid is recovered as a white ash. This is a typical example of an oxidation reaction which is also a combustion reaction.

The reason has nothing at all to do with the assertion hence the answer given.

Magnesium oxide is basic just like the oxides of other metals and dissolves in water to yield an alkali.

8 0

3 years ago

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What is the empirical formula for a compound if 300.00 g of it is known to contain 82.46224 g of molybdenum, 45.741 g of chlorin

Marysya12 [62]

Answer:

MoClBr₂

Explanation:

First we calculate the mass of bromine in the compound:

300.00 g - (82.46224 g + 45.741 g) = 171.79676 g

Then we calculate the number of moles of each element, using their respective molar masses:

82.46224 g Mo ÷ 95.95 g/mol = 0.9594 mol Mo

45.741 g Cl ÷ 35.45 g/mol = 1.290 mol Cl

171.79676 g Br ÷79.9 g/mol = 2.150 mol Br

Now we divide those numbers of moles by the lowest number among them:

0.9594 mol Mo / 0.9594 = 1

1.290 mol Cl / 0.9594 = 1.34 ≅ 1

2.150 mol Br / 0.9594 = 2.24 ≅ 2

Meaning the empirical formula is MoClBr₂.

8 0

3 years ago

A negatively charged particle has too many ___