Answer:
A = 2-iodo-2,3-dimethylbutane
B = Ethanol
C = Iodoethane (also called ethyl-iodide)
Explanation:
2-Ethoxy-2,3-dimethylbutane reacts with conc. HI to cleave the oxy-functional group.
On one end, ethanol is formed and on the other hand, 2-iodo-2,3-dimethylbutane is formed.
But ethanol reacts further with conc HI to give iodoethane.
Therefore,
A = 2-iodo-2,3-dimethylbutane
B = Ethanol
C = Iodoethane (also called ethyl-iodide)
This is all shown in the attached image.
Hope this Helps!!!
Phosphorylation is a process in which addition of phosphoryl group is added. This process explains the presence of the PO₃⁻ in the molecules. One type of phosphorylation is that which is termed as the substrate-level phosphorylation. This is a metabolic reaction that allows or results to the formation of ATP due to the direct transfer of phosphoryl to ADP.
Hence, the answer is ATP.
Hey there,
I hope this answer solves your doubt.
<u>S</u><u>t</u><u>e</u><u>p</u><u>-</u><u>b</u><u>y</u><u>-</u><u>s</u><u>t</u><u>e</u><u>p</u><u> </u><u>Expla</u><u>n</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u>
The question is asking if the bonds between Carbon and Chlorine in CCl4 will be single, double or triple bonds.
<em>(</em><em>The structure of CCl4 </em><em>i</em><em>s attached as picture. Check it</em><em>)</em>
As per image, the structure consists of <u>Singl</u><u>e</u><u> </u><u>b</u><u>o</u><u>n</u><u>d</u><u>s</u><u>.</u> It is <u>4 single bonds</u>.
The component that runs the circuit is C the wire