I assume that the ball is stationary (v=0) at point B, so its total energy is just potential energy, and it is equal to 7.35 J.
At point A, all this energy has converted into kinetic energy, which is:

And since K=7.35 J, we can find the velocity, v:
The sweater has a tendency to attract electrons.
The leather jacket has a lower tendency to attract electrons than the sweater.
Explanation:
The sweater and the leather jackets are made up of distinct fabrics that based on their minutest particles called an atom.
An atom is made up of sub-atomic particles of protons, neutrons and electrons.
- Electrons occupies the bulk volume of the atom and they are easily lost in atoms that are big. They are negatively charged.
- Protons are positively charged and are very difficult to lose. They occupy the tiny nucleus with neutrons.
- A body that becomes negatively charged will be said to have a hihg tendency to attract electrons. Normally atoms are electrically neutral. When additional electrons are added to them, they become negatively charged.
- In this case, the sweater has a high affinity for electrons and it will attract the ones on the leather jacket.
- The leather jacket has a low tendency to attract electrons than the sweater and it will lose some of its electrons to the sweater.
Learn more:
Protons, neutrons and electrons brainly.com/question/2757829
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In order to solve the problem, it is necessary to apply the concepts related to the conservation of momentum, especially when there is an impact or the throwing of an object.
The equation that defines the linear moment is given by

where,
m=Total mass
Mass of Object
Velocity before throwing
Final Velocity
Velocity of Object
Our values are:

Solving to find the final speed, after throwing the object we have

We have three objects. For each object a launch is made so the final mass (denominator) will begin to be subtracted successively. In addition, during each new launch the initial speed will be given for each object thrown again.
That way during each section the equations should be modified depending on the previous one, let's start:
A) 



B) 



C) 



Therefore the final velocity of astronaut is 3.63m/s
The two most common units of electric energy is Watts or hertz.