A container contains 200g of water at initial temperature of 30°C. An iron nail of mass 200g at temperature of 50°C is immersed
2 answers:
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The rest energy of a particle is
where
is the rest mass of the particle and c is the speed of light.
The total energy of a relativistic particle is
where v is the speed of the particle.
We want the total energy of the particle to be twice its rest energy, so that
which means:
From which we find the ratio between the speed of the particle v and the speed of light c:
So, the particle should travel at 0.87c in order to have its total energy equal to twice its rest energy.
where
The total energy of a relativistic particle is
where v is the speed of the particle.
We want the total energy of the particle to be twice its rest energy, so that
which means:
From which we find the ratio between the speed of the particle v and the speed of light c:
So, the particle should travel at 0.87c in order to have its total energy equal to twice its rest energy.
Answer:
a) W = - 6.825 J, b) θ = 1.72 revolution
Explanation:
a) In this exercise the work of the friction force is negative and is equal to the variation of the kinetic energy of the particle
W = ΔK
W = K_f - K₀
W = ½ m v_f² - ½ m v₀²
W = ½ 0.325 (5.5² - 8.5²)
W = - 6.825 J
b) find us the coefficient of friction
Let's use Newton's second law
fr = μ N
y-axis (vertical) N-W = 0
fr = μ W
work is defined by
W = F d
the distance traveled in a revolution is
d₀ = 2π r
W = μ mg d₀ = -6.825
μ =
The total work as the object stops the final velocity is zero v_f = 0
W = 0 - ½ m v₀²
W = - ½ 0.325 8.5²
W = - 11.74 J
μ mg d = -11.74
we subtitle the friction coefficient value
( ) m g d = -11.74
6.825 = 11.74
d = 11.74/6.825 d₀
d = 1.7201 2π 0.400
d = 4.32 m
this is the total distance traveled, the distance and the angle are related
θ = d / r
θ = 4.32 / 0.40
θ = 10.808 rad
we reduce to revolutions
θ = 10.808 rad (1rev / 2π rad)
θ = 1.72 revolution