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taurus [48]
4 years ago
12

A compound with the empirical formula ch2 has a molar mass of 70 g/mol. what is the molecular formula for this compound?

Chemistry
2 answers:
Lena [83]4 years ago
6 0

Answer:

C12H24

Explanation:

on apex

Rainbow [258]4 years ago
5 0

The empirical formula, <span>C<span>H2</span></span>, has a relative molecular mass of

<span>1×<span>(12.01)</span>+2×<span>(1.01)</span>=14.04</span>

This means that the empirical formula must be multiplied by a factor to bring up its molecular weight to 70. This factor can be calculated as the ratio of the relative masses of the molecular and empirical formulas

<span><span>7014.04</span>=4.98≈5</span>

Remember that subscripts in molecular formulas must be in whole numbers, hence the rounding-off. Finally, the molecular formula is

<span><span>C<span>1×5</span></span><span>H<span>2×5</span></span>=<span>C5</span><span>H<span>10</span></span></span>

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Answer:

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Explanation

Firstly, It is considered as a stichiometry problem.

From the balanced equation: 2LiCl → 2Li + Cl₂

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n = (30.3 g) / (6.941 g/mole) = 4.365 moles.

Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.

Using cross multiplication:

2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.

??? moles of LiCl → 4.365  moles of Li.

The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.

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