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Law Incorporation [45]
3 years ago
10

What happens to the principle energy level number when moving from s to p sub levels

Chemistry
1 answer:
Leni [432]3 years ago
8 0

Answer:

The principal energy level remains the same

Explanation:

A principal energy level is one defines where electrons reside in an atom and that can contain one or more sub levels and have 2·n² number of electrons located in different sub levels within the energy level. Therefore, when moving up from s to p within the same principal energy level, the principal energy level does not change value.

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if kept at a constant temperature, what is the concentration at 865s if the initial concentration was 0.0225M
Anestetic [448]

Answer:

[SO_2Cl_2]=0.0175M

Explanation:

Hello!

In this case, considering that the decomposition reaction of SO2Cl2 is first-order, we can write the rate law shown below:

r=-k[SO_2Cl_2]

We also consider that the integrated rate law has been already reported as:

[SO_2Cl_2]=[SO_2Cl_2]_0exp(-kt)

Thus, by plugging in the initial concentration, rate constant and elapsed time we obtain:

[SO_2Cl_2]=0.0225Mexp(-2.90x10^{-4}s^{-1}*865s)

[SO_2Cl_2]=0.0175M

Best regards!

8 0
2 years ago
Potassium nitrate has a lattice energy of -163.8 kcal/mol and a heat of hydration of -155.5 kcal/mol.
Brut [27]

Answer:

<em>293.99 g </em>

OR

<em>0.293 Kg</em>

Explanation:

Given data:

Lattice energy of Potassium nitrate (KNO3) = -163.8 kcal/mol

Heat of hydration of KNO3 = -155.5 kcal/mol

Heat to absorb by KNO3 = 101kJ

To find:

Mass of KNO3 to dissolve in water = ?

Solution:

Heat of solution = Hydration energy - Lattice energy

                           = -155.5 -(-163.8)

                           = 8.3 kcal/mol

We already know,

1 kcal/mol = 4.184 kJ/mole

Therefore,

= 4.184 kJ/mol x 8.3 kcal/mol

= 34.73 kJ/mol

Now, 34.73 kJ of heat is absorbed when 1 mole of KNO3 is dissolved in water.

For 101 kJ of heat would be

= 101/34.73

= 2.908 moles of KNO3

Molar mass of KNO3 = 101.1 g/mole

Mass of KNO3 = Molar mass x moles

                         = 101.1 g/mole  x  2.908

                         = 293.99 g

                         = 0.293 kg

<em><u>293.99 g potassium nitrate has to dissolve in water to absorb 101 kJ of heat. </u></em>     

4 0
3 years ago
Which ecosystem is more likely to become unstable one with many kinds of plants and animals or one with few kinds?
Art [367]

Answer:

One with a few kinds is more likely to become unstable.

Explanation:

A lack of biodiversity means there is a lower chance of them having traits that enable them to adapt to a changing environment. A lack of biodiversity is usually caused by humans. It could be the result of habitat loss, invasive species, overexploitation, pollution, or climate change.

5 0
2 years ago
Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
olga55 [171]

Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

x = order with respect to A

y = order with respect to A

n = x+y = Total order

a) From trial 1: 1.2\times 10^{-2}=k[0.10]^x[0.20]^y    (1)

From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

Dividing 2 by 1 :\frac{4.8\times 10^{-2}}{1.2\times 10^{-2}}=\frac{k[0.10]^x[0.40]^y}{k[0.10]^x[0.20]^y}

4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

2=2^x,2=2^1, x=1

Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



6 0
3 years ago
My test is tomorrow and I'm confused about how to solve these. pls halp
Stels [109]

Answer:

Explanation:

  1. <em><u>I</u></em><em><u> </u></em><em><u>don't</u></em><em><u> </u></em><em><u>know</u></em><em><u> </u></em>
  2. <em><u>BCAZ</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>don't</u></em><em><u> </u></em><em><u>know</u></em>
  3. <em><u>And</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>don't</u></em><em><u> </u></em><em><u>know</u></em>
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5 0
2 years ago
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