How can a change in mass affect the motion on an object? Explain how you got the answer step-by-step
1 answer:
Explanation:
- Okay so if lets start with a law of motion. (Newtons second law of motion)*The rate of change of momentum is proportional to the resultant force and occurs in the directional force*.
- This means that f = ma *the attached image shows how to get here *
- since f is the force is the one needed to 'obtain' the motion you will notice that if my value of m changes my f chances for example lets take a to be 1 (keep it constant)
- lets have m=3 or 120, will change likewise f
- a change in f means a change in motion be it deceleration or acceleration
- l hope this makes sense and l hope that it's correct
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The answer is a path of destruction up to 50 miles long with destroyed trees and homes.
Tornadoes form from severe thunderstorms. Wind in the higher altitude of the storm moving at a greater velocity than wind at a lower altitude creates a vertical wind shear. The faster-moving winds aloft come from the west and create an updraft when they meet slower-moving wind close to the ground that is moving in the opposite direction. As warm surface air moves upward into the thundercloud, the rotating air creates a vortex.
The image below shows before and after damage of a tornado.
Answer:
t = 1.4[s]
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.
where:
P = impulse or lineal momentum [kg*m/s]
m = mass = 50 [kg]
v = velocity [m/s]
F = force = 200[N]
t = time = [s]
Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.
where:
m₁ = mass of the object = 50 [kg]
v₁ = velocity of the object before the impulse = 18.2 [m/s]
v₂ = velocity of the object after the impulse = 12.6 [m/s]
Answer:
Efficiency = 52%
Explanation:
Given:
First stage
heat absorbed, Q₁ at temperature T₁ = 500 K
Heat released, Q₂ at temperature T₂ = 430 K
and the work done is W₁
Second stage
Heat released, Q₂ at temperature T₂ = 430 K
Heat released, Q₃ at temperature T₃ = 240 K
and the work done is W₂
Total work done, W = W₁ + W₂
Now,
The efficiency is given as:
or
Work done = change in heat
thus,
W₁ = Q₁ - Q₂
W₂ = Q₂ - Q₃
Thus,
or
or
also,
or
thus,
thus,
or
or
Efficiency = 52%