First, you would add the products: 0.4 + 6.01 = 6.41 g
Then, to get the mass of Iron required, you would do 6.41 - 5.0 = 1.41
This is because in the conservation of mass principle it states,
mass of reactants = mass of products.
<span> a. carbon-14 b. phosphorus-32 c. potassium-40 d. rubidium-87
d</span>
Answer:
Mass = 0.00541 g
Explanation:
We will convert the larger given values in to smaller by rounding these figures.
Given data:
Mass of zinc sulfide = 43 g
Mass of oxygen = 44.2 g
Mass of zinc oxide = ?
Solution:
Chemical equation:
2ZnS + 3O₂ → 2ZnO + 3SO₂
Number of moles of ZnS:
<em>Number of moles = mass/ molar mass </em>
Number of moles = 43 g/ 97.5 g/mol
Number of moles = 0.44 mol
Number of moles of Oxygen:
<em>Number of moles = mass/ molar mass </em>
Number of moles = 44.2 g/ 32 g/mol
Number of moles = 1.4 mol
Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.
ZnS : ZnO
2 : 2
0.44 : 0.44
O₂ : ZnO
3 : 2
1.4 : 2/3×1.4 =0.93
The number of moles of zinc oxide produced by ZnS are less so it will limiting reactant.
Mass of zinc oxide:
Mass = number of moles / molar mass
Mass = 0.44 mol / 81.38 g/mol
Mass = 0.00541 g
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Balancing the equation, we get:
2C₂H₆O + O₂ → 2C₂H₄O₂ + 2H₂O
So
α = 2
β = 1
γ = 2
δ = 2
