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Ket [755]
3 years ago
12

What is the charge on an electron?

Chemistry
2 answers:
wariber [46]3 years ago
4 0

Answer:

positive

Explanation:

xxTIMURxx [149]3 years ago
3 0

Answer

1.60217662 × 10-19 coulombs

Explanation:

.

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Which of the following chemical agents is used for sterilization? Which of the following chemical agents is used for sterilizati
lozanna [386]

Answer:

The correct answer is super critical fluids.

Explanation:

Supercritical fluids are the fluids which are compressed below their critical temperature, kept in liquid state and used above their boiling point.The most common example of this are : liquid carbon dioxide gas and water.

  • They have properties of gas and liquid.
  • They can easily effuse through solids like gas and dissolves other substance in them like liquid.
3 0
2 years ago
Each of the following reactions is allowed to reach equilibrium in a sealed container. For which of the reactions could you shif
natta225 [31]

Answer:

None of the reaction will be favored to the right by a decrease in pressure.

Explanation:

       CH₄(g) + 2O₂(g) ⇄ CO₂(g) + 2H₂O(l)  

       CaCO₃(s) ⇄  CaO(s) + CO₂(g)  

       Br₂(g) + 3Cl₂(g) ⇄  2BrCl₃(g)  

       2H₂S(g) + 3O₂(g) ⇄  2SO₂(g) + 2H₂O(g)

From Le Chatellier's principle, we must understand that pressure changes only affects reactions in gaseous phases. The second reaction will not be affected by pressure.

We are now left with three equations.

Also, increase in pressure favors sides with lower volume. We can know the volume from the coefficients in the equation. Now let us check the volumes:

          CH₄(g) + 2O₂(g) ⇄ CO₂(g) + 2H₂O(l)  

         3 moles of gases      3 moles of gases

        Br₂(g) + 3Cl₂(g) ⇄  2BrCl₃(g)  

         4 moles of gases     2 moles of gases

       2H₂S(g) + 3O₂(g) ⇄  2SO₂(g) + 2H₂O(g)

        5 moles of gases      4 moles of gases

None of the reaction will be favored to the right by a decrease in pressure.

The first reaction will not be affected by any change in pressure because the total number of moles on the two sides are equal.

The last two reactions will be favored to the right by increasing pressure and a decrease in pressure will favor the backward left reaction.

7 0
3 years ago
Read 2 more answers
Help me please I need help
yanalaym [24]
37. Is D
38. Is C
39. Is A
40. Is A
41. Is D I think!
I'm 100% positive about 37-40 but I'm 50% sure on question number 41.
I hope this helped!
4 0
3 years ago
¿Cuáles son las características de los materiales de laboratorio? Por ejemplo: exactitud, resistencia a la temperatura, etc.
irina [24]

Answer:

gfchjklnmbvh

Explanation:

4 0
2 years ago
Read 2 more answers
A compound has been shown to contain 14.5 percent hydrogen and 85.5 percent carbon by mass.
Sedaia [141]

Answer:

  • <em>Option d. Its empirical formula is CH</em><em>₂</em><em>.</em>

Explanation:

The percent composition of the compound allow you to calculate the empirical formula of the compound but is not enough to calculate either the molar mass or the molecular formula. So, since now you can discard options b. and c.

Telling that it is a hydrocarbon (option e.) is true but very vague compared with finding the empirical formula. So, you can also discard the option e.

The fact that the product has a triple bond cannot be concluded from the percent composition, you should find the molecular formula to assert whether it contains or not a triple bond. So, you could discard option a., which lets you only with choice d.

Let us find the empirical formula to be certain that it is CH₂.

1.  <u>First, assume a basis of 100 g of compound</u>:

  • H: 14.5% × 100 g = 14.0 g
  • C: 85.5% × 100 g = 85.5 g

2. <u>Divide each element by its atomic mass to find number of moles</u>:

  • H: 14.0 g / 1.008 g/mol = 14.38 mol
  • C: 85.5 g / 12.011 g/mol = 7.12 mol

3. <u>Divide both amounts by the smallest number, to find the mole ratio</u>:

  • H: 14.38 mol / 7.12 mol ≈ 2
  • C: 7.12 mol / 7.12 mol = 1.

Hence, the ratio is 2:1 and the empirical formula is CH₂.

7 0
3 years ago
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