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Bezzdna [24]
3 years ago
12

which of the following substances have polar interactions (dipole-dipole forces) between molecules? F2, Cl2, ClF, NF3

Chemistry
2 answers:
Alex787 [66]3 years ago
5 0
F2 and Cl2 are non-polar because both contains same atom and they have same electronegativity.

ClF and NF3 have polar interactions because there is electronegativity difference between atoms.

Hope this helps!
serious [3.7K]3 years ago
3 0

Answer:

Explanation:

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas. The shared electron pair is common to the two atoms and holds them together.

Electronegativity is defined as the ability of an element to attract the electrons that link it to another element.

The covalent bond between two atoms can be polar or nonpolar.

When two atoms have different electronegativities, the one with the highest electronegativity will attract the electrons towards each other, giving rise to two opposite charges on the bond. That is, this generates that in a polar molecule there is separation between positive and negative charges. The bonds will be all the more polar the greater the difference in electronegativity between the bound atoms.

On the other hand, the non-polar covalent bond occurs between atoms of the same element or between atoms with very little electronegativity difference. It is thus characterized to molecules or bonds that do not exhibit any polarity.

A molecule is a dipole when there is an asymmetric distribution of electrons because the molecule is made up of atoms of different electronegativity. That is, dipole is formed when the molecule is polar.

So, dipole-dipole forces are forces of attraction between polar molecules. These molecules attract when the positive end of one of them is close to the negative of the other.

Given the above, F₂ and Cl₂ are non-polar molecules and ClF and NF₃ are polar molecules. Then ClF and NF₃ have polar interactions (dipole-dipole forces).

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Express the product of 9.0 x 10^-4m and 8.1 x 10^4m using the correct number of significant digits
Assoli18 [71]

Answer:

7.3 × 10¹ m²

Explanation:

The language "product" means that we must multiply the numbers given to get our answer.

9.0 × 10⁻⁴ m × 8.1 × 10⁴ m = 7.3 × 10¹ m²

The significant figures rule for multiplication is that we must us the amount of significant figures in the number with the least significant figures, in this question this is 2 significant digits from both 9.0 × 10⁻⁴ m and 8.1 × 10⁴ m.

7 0
4 years ago
How many grams of iron (III) chloride must decompose to produce 78.4 milliliters of iron metal, if the density of iron is 7.87 g
irga5000 [103]
<span>I think this is the correct Answer

the balanced equation is

2 FeCl3 = 2 Fe + 3 Cl2

volume Fe = 78.4 mL / 7.87 g/mL = 9.96 g

moles Fe = 9.96 g / 55.847 g/mL=0.178

the ratio between FeCl3 and Fe is 2 : 2

moles FeCl3 = 0.178

mass FeCl3 = 0.178 x 162.206 g/mL=28.9 g</span>

Not Completely sure though, But
Hope It Helps
3 0
4 years ago
Read 2 more answers
What is the mass of an aluminum cylinder with 0.234 in diameter and a length of 2.697
Lemur [1.5K]

0.33g

Explanation:

Given parameters:

Diameter of cylinder = 0.234cm

length = 2.697cm

unknown:

mass of the cylinder = ?

Solution:

To solve this problem, we know that density of the aluminium can be determined and it is a constant.

 Density is the mass per unit volume of a substance

 Density = \frac{mass}{volume}

 Mass of the cylinder = density x volume

To calculate the volume of cylinder;

  Volume = π r² h

     radius of the cylinder = \frac{0.234}{2} = 0.12cm

Volume = 3.142 x 0.12² x 2.697 = 0.12cm³

Density of aluminium = 2.7g/cm³

 Mass of the cylinder = 0.12 x 2.7 = 0.33g

learn more:

Density brainly.com/question/2690299

#learnwithBrainly

8 0
4 years ago
An Erlenmeyer flask containing 20.0 mL of sulfuric acid of an unknown concentration was titrated with exactly 15.0 mL of 0.25 M
MrRa [10]

Answer:

0.09375M

Explanation:

There are two methods of going about this, either we use dilution formula (easiest and fastest) or we solve through molarity.

Using dilution formula,

C2 (H2SO4) = ?

C1 (NaOH) = 0.25M

V2 (H2SO4) = 20cm³

V1 (NaOH) = 15cm³

However we can solve using molarity method

Equation of reaction =

2NaOH + H2SO4 ====》 Na2SO4 + 2H2O

O.25M of NaOH = 1000cm³

X moles = 15cm³

X = (0.25 * 15) / 1000

X = 0.00375 moles is present in 15cm³ of NaOH

From equation of reaction,

2 moles of NaOH requires 1 mole of H2SO4

Therefore

0.00375 / 2 = 0.001875 moles is present in H2SO4

From the reaction,

0.00187 moles of H2SO4 = 20 cm³

X moles = 1000cm³

X = (0.00187*1000) / 20 = 0.09375M

8 0
3 years ago
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