Answer:
The force exerted is 318.86 N
Explanation:
The force exerted by such a stream is calculated by multiplying the mass flow rate of water by the velocity of the stream of water.
mass flow rate = 21.4 kg/s
velocity = 14.9 m/s
Force exerted = 21.4 kg/s × 14.9 m/s = 318.86 kgm/s^2 = 318.86 N
To get the solution you must need to draw a force triangle. Attach the head of the 60N north force arrow with the tail of the 60N east force arrow. The subsequent is the arrow connecting he tail and head of the two arrows.
You get a right angled triangle, and the resultant is (60^2 + 60^2) ^0.5 = 84.85 N or 85 N northeast.
1.7 Btu
1 watt = 3.41214 Btu/h
1watt * 1h = 3.41214 Btu/h * h
1 = 3.41214 Btu/ (watt*h)/
0.5 watt * h = 0.5 watt*h * 3.41214 Btu/(watt*h) = 1.706 Btu
Answer:
Pressure = ρgh
pressure (p) is measured in pascals (Pa)
density (ρ) is measured in kilograms per metre cubed (kg/m3)
The fore of gravitational field strength (g) is measured in N/kg or m/s 2
height of column (h) is measured in metres (m)
Answer = 235,200 Pa
Explanation:
Pressure = ρgh
Pressure = 1,000 x 9.8 x 24
Pressure = 235,200 Pa
Answer:
The average speed can be calculated as the quotient between the distance travelled and the time needed to travel that distance.
To go to the school, he travels 2.4 km in 0.6 hours, then here the average speed is:
s = (2.4km)/(0.6 hours) = 4 km/h
To return to his home, he travels 2.4km again, this time in only 0.4 hours, then here the average speed is:
s' = (2.4 km)/(0.4 hours) = 6 km/h.
Now, if we want the total average speed (of going and returning) we have that the total distance traveled is two times the distance between his home and school, and the total time is 0.6 hours plus 0.4 hours, then the average speed is:
S = (2*2.4 km)/(0.6 hours + 0.4 hours)
S = (4.8km)/(1 h) = 4.8 km/h
