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dimulka [17.4K]
3 years ago
14

Compare the results of applying the acceleration equation in the following 2 cases : (1) an object that goes from 0 to 10 m/s in

4 s , and (2) then goes from 10 m/s to 30 m/s in 8s.
a= (Vf-Vs)/t
Physics
1 answer:
erastovalidia [21]3 years ago
8 0

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a 1-kg discus is thrown with a velocity of 19 m/s at an angle of 35 degrees from the vertical direction. calculate the vertical
nlexa [21]

Answer:

Vx =  10.9 m/s ,  Vy = 15.6 m/s

Explanation:

Given velocity V= 19 m/s

the angle 35 ° is taken from Y-axis so the angle with x-axis will be 90°-35° = 55°

θ = 55°

to Find Vx = ? and Vy= ?

Vx = V cos θ

Vx = 19 m/s  × cos 55°

Vx =  10.9 m/s

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Vy = 19 m/s  × sin 55°

Vy = 15.6 m/s

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Answer: A.

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