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mylen [45]
3 years ago
15

HELP ME, PLEASE.

Physics
2 answers:
Wittaler [7]3 years ago
8 0
I would say tempurature
Leno4ka [110]3 years ago
4 0
The temperature determines the star's color.
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At the bottom of a frictionless ramp, a 2kg mass reaches a speed of 9 m/s, how high is the top of the ramp? *
noname [10]
V=√(2gs)
9=√(2×9.8×s)
s=4.1m
3 0
3 years ago
The 4.0 -kg head of an ax is moving at 3 m/s when it strikes a log and penetrates 0.01m into the log. What is the average force
Elina [12.6K]

Answer:

the average force the blade exerts on the log is 1791.05 N.

Explanation:

Given;

mass of the ax head, m = 4 kg

speed of the ax, v = 3 m/s

depth traveled into the log, d = 0.01 m

The time to traveled through the depth;

s = (\frac{u+v}{2} )t\\\\0.01 =  (\frac{0+3}{2} )t\\\\0.01 = 1.5t\\\\t = \frac{0.01}{1.5} \\\\t = 0.0067 \ s

The average force the blade exerts on the log;

F = ma=\frac{mv}{t} = \frac{4 \times 3}{0.0067} = 1791.05 \ N \\\\

Therefore, the average force the blade exerts on the log is 1791.05 N.

5 0
3 years ago
A body of mass 200gram is executing SHM with amplitude of 20mm. The magnitude of maximum force which acts upon it is 0.6N. Calcu
igor_vitrenko [27]

The value of maximum velocity will be 0.3464 m/s². Energy or work is equal to the product of force and displacement.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

Mass of the body is,(m= 200g)

Amplitude is,(A  =20 mm)

Maximum force is,F= 0.6 N

To find;

Maximum velocity

Energy or work is equal to the product of force and displacement.

\rm KE = \frac{1}{2} mV_{max}^2 \\\\ \rm F_{max} \times A = \frac{1}{2} mV_{max}^2 \\\\ F_{max}= \frac{1}{2}\frac{ mV_{max}^2}{A} \\\\ 0.6= \frac{1}{2}\times \frac{ 0.2 \times V_{max}^2}{20 \times 10^{-3}} \\\\ V_{max}=0.3464 \ m/sec^2

Hence,the value of maximum velocity will be 0.3464 m/s².

To learn more about the velocity, refer to the link;

brainly.com/question/862972

#SPJ2

7 0
2 years ago
Read 2 more answers
A pogo stick has a spring with a force constant of 2.50 × 104 N/m , which can be compressed 11.2 cm. what maximum height, in met
AleksandrR [38]

Answer:

h = 36.4 cm

Explanation:

given,

spring constant = 2.5 x 10⁴ N/m

compressed distance = 11.2 cm = 0.112 m

mass of the child = 44 kg

maximum height = ?

by energy of conservation

K.E_i +P.E_i= K.E_f + P.E_f

\dfrac{1}{2}kx^2 = mgh

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

156.8 = 44 \times 9.8 \times h

h = \dfrac{156.8}{44 \times 9.8}

h = 0.364 m

h = 36.4 cm

7 0
3 years ago
Is the relationship between the length of a pendulum and its period is valid at all times?
Stels [109]
Yes it is valid all the times under the consideration of acceleration due to gravity .it is not valid on space where there is no influence of gravity
4 0
3 years ago
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