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3 years ago

Draw the structure of ozone according to VSEPR theory. What would be its associated molecular geometry?

Chemistry

1 answer:

vodka [1.7K]3 years ago

8 0

Answer: Ozone's molecular geometry can be described as bent.

Explanation:

The molecular geometry of the O3 groups has a trigonal planar arrangement.

Here is a quick explanation of the molecular geometry of O3 including a quick description of the O3 bond angles.

Examining the Lewis structure of O3 we can see that there are a pair of unbounded valence electrons at the top of the structure.

Based on VSEPR Theory (Valence Shell Electron Pair Repulsion Theory) these electrons will repel the electron clouds of the two oxygen atoms on the end.

As a result they will be pushed down giving the 03 molecule a bent molecular geometry or shape.

The 03 bond angle will be 116° degrees since it has a Bent molecular geometry

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A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.

nata0808 [166]

The equilibrium constant for this reaction at 350°C is determined as 5.85.

<h3>Concentration of each component</h3>

concentration of bromine, C(Br) = 0.6 mol/1 = 0.6

concentration of iodine, C(I) = 1.6 mol/1 = 1.6

<h3>Create an ICE table</h3><h3>What is ICE table?</h3>

An ICE table is a tabular system of keeping track of changing concentrations in an equilibrium reaction.

ICE is an abbreviation that stands for initial, change, equilibrium.

Create ICE table for the reactants and products formed;

Br2(g) + I2(g) ↔ 2IBr(g)

I 0.6 1.6 0

C -1.19 -1.19 1.19

E 0.6 - 1.19 1.6 - 1.19 1.19

E = -0.59 0.41 1.19

<h3>Equilibrium constant </h3>

The equilibrium constant is calculated as follows;

KC = [IBr]²/[Br][I]

KC = (1.19²) / (0.59 x 0.41)

KC = 5.85

Thus, the equilibrium constant for this reaction at 350°C is determined as 5.85.

Learn more about equilibrium constant here: brainly.com/question/19340344

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4 0

2 years ago

NEED HELP ASAP PLEASE

Lostsunrise [7]

Answer:

here hope it helps

Explanation:

covalent bonds

5 0

3 years ago

Read 2 more answers

A gas at constant volume has a pressure of 4. 50 atm at 200. K. What will be the pressure of the gas at 250. K? 3. 60 atm 4. 60

Trava [24]

5.625 atm will be the pressure of the gas at 250 K temperature of the gas at constant volume.

<h3>How we calculate the pressure of the gas?</h3>

Pressure of the gas will be calculated by using the ideal gas equation as:

PV = nRT,

From the question, it is clear that:

Moles of the gas and volume is constant here, so we calculate the pressure by rearranging the above equation as:

P/T = nR/V

And required equation will be:

P₁/T₁ = P₂/T₂, where

P₁ = pressure of gas = 4.50 atm

T₁ = temperature of gas = 200 K

P₂ = pressure of gas = to find?

T₂ = temperature of gas = 250 K

On putting all these values in the above equation, we get

P₂ = 4.50 × 250 / 200 = 5.625 atm

Hence, 5.625 atm is the pressure of the gas.

To know more about ideal gas equation, visit the below link:

brainly.com/question/1056445

5 0

3 years ago

How many moles do you need to prepare 1.675 L of a 8.50 M NaOH solution? Round your answer to 2 decimal places.

vampirchik [111]

Answer:

0.20 mol's

Explanation:

1.675 L = 1.675 dm^3

moles = V/(conc):

moles = 1.675/(8.5)

moles = 0.1970... --> 0.20

7 0

3 years ago

Read 2 more answers

Which one of the following classes of organic compound does not contain the carbonyl (C=O) group?A) aldehydesB) carboxylic acids

vredina [299]

Answer: alcohols

Explanation:

The carbonyl group refers to C=O. It is contained in aldehyde, Ketones, carboxylic acids , esters, amides and acyl chlorides. They are not found in alcohols. The alchols are generally ROH. They do not contain any carbon-oxygen unsaturated bond in their structure hence the answer.

3 0

3 years ago