Answer:
Approximately 
(assuming that the projectile was launched at angle of 
above the horizon.)
Explanation:
Initial vertical component of velocity:
.
The question assumed that there is no drag on this projectile. Additionally, the altitude of this projectile just before landing 
is the same as the altitude 
at which this projectile was launched: 
.
Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is 
(upwards,) the vertical velocity right before landing would be 
(downwards.) The change in vertical velocity is:
.
Since there is no drag on this projectile, the vertical acceleration of this projectile would be 
. In other words, 
.
Hence, the time it takes to achieve a (vertical) velocity change of 
would be:
.
Hence, this projectile would be in the air for approximately .
Answer:
Option C. The force between them would be 4 times larger than with the
initial masses.
Explanation:
To know which option is correct, we shall determine the force of attraction between the two masses when their masses are doubled. This can be obtained as follow:
From:
F = GMₐM₆/ r²
Keeping G/r² constant, we have
F₁ = MₐM₆
Let the initial mass of both objects to be m
F₁ = MₐM₆
F₁ = m × m
F₁ = m²
Next, let the masses of both objects doubles i.e 2m
F₂ = MₐM₆
F₂ = 2m × 2m
F₂ = 4m²
Compare the initial and final force
Initial force (F₁) = m²
Final (F₂) = 4m²
F₂ / F₁ = 4m² / m²
F₂ / F₁ = 4
F₂ = 4F₁ = 4m²
From the above illustrations, we can see that when the mass of both objects doubles, the force between them would be 4 times larger than with the
initial masses.
Thus, option C gives the correct answer to the question.
Please find attached photograph for your answer. Please do comment whether it is useful or not
Answer:
The current pass the 
is 
Explanation:
The diagram for this question is shown on the first uploaded image
From the question we are told that
The voltage is 
The first resistance is 
The second resistance is 
Since the resistors are connected in series their equivalent resistance is
Substituting values
Since the resistance are connected in serie the current passing through the circuit is the same current passing through which is mathematically evaluated as
Substituting values
