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irinina [24]
2 years ago
13

Two objects are placed on a scale so that it balances. One object weighs 5 N and is placed 0.5 m from the fulcrum of the scale.

The other object is placed 1 m from the fulcrum. How heavy is the other object?
Physics
1 answer:
insens350 [35]2 years ago
5 0

The weight of the other object placed 1 m from the fulcrum that balances the other object is 2.5 N.

<h3>Principle of moment</h3>

The weight of the second object is determined by applying principle of moment as shown below;

take moment about the pivot,

sum of clockwise moment = sum of anticlockwise moment

F₁r₁ = F₂r₂

5 x 0.5 = F₂ x 1

2.5 N = F₂

Thus, the weight of the other object placed 1 m from the fulcrum that balances the other object is 2.5 N.

Learn more about moment here: brainly.com/question/6278006

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A elephant kicks a 5.0\,\text {kg}5.0kg5, point, 0, start text, k, g, end text stone with 150\,\text J150J150, start text, J, en
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The speed of the stone is 7.7 m/s

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The kinetic energy of a body is the energy possessed by the body due to its motion. Mathematically,

K=\frac{1}{2}mv^2

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v is its speed

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m = 5.0 kg is its mass

Re-arranging the equation for v, we find the speed of the stone:

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A satellite omass1000 kg moves in a circular orbit of radius 8000 km round the earth,assumed to be a sphere of radius 6400 km. C
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Answer:

ΔE = 37.8 x 10^9 J

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The energy required will increased the potential energy and increase the kinetic energy.

As the altitude change is fairly small compared to the earth radius, we can ASSUME that the average gravity will be a good representative

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G(avg) = (9.8 + 6.272)/2 = 8.036 m/s²

ΔPE = mG(avg)Δh = 1000(8.036)(8e6 - 6.4e6) = 12.857e9 J

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The maximum velocity when resting on earth at the equator is about 460 m/s.

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