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3 years ago

What feature on earth plays a role in the carben cycle similar to that of forests? explain

Physics

1 answer:

andriy [413]3 years ago

3 0

Carbon can be in the atmosphere, water and in organisms

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Which statement is true for both types of transistors?

lara31 [8.8K]

For both NPN and PNP this is true:

The base is between the collector and the emitter.

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3 years ago

Read 2 more answers

Water flows over a section of Niagara Falls at rate of 1.1×10^6 kg/s and falls 49.4 m. How much power is generated by the fallin

DerKrebs [107]

Answer:

The power generated is = 5.33×10⁸ Watt.

Explanation:

Power: Power can be defined as the time rate of doing work. The S.I unit of power is Watt(W).

Mathematically,

Power (P) = Work done/time or Energy/time

P = mgh/t............................... Equation 1

P = δgh............................. Equation 2

Where δ = fall rate, g = acceleration due to gravity, h = height.

Given: δ = 1.1×10⁶ kg/s, h = 49.4 m g = 9.81 m/s²

Substituting these values into equation 2

P = 1.1×10⁶×49.4×9.81

P = 533.08×10⁶

P = 5.33×10⁸ Watt.

Thus the power generated is = 5.33×10⁸ Watt.

5 0

3 years ago

The current in a stream runs at 5 miles per hour. if a boat can go 15 miles per hour on still water, how fast can the boat go do

arsen [322]

Down stream it would be going 20 mph and up stream 10 mph

3 0

3 years ago

From January 26, 1977, to September 18, 1983, George Meegan of Great Britain walked from Ushuaia, at the southern tip of South A

Nikolay [14]

Answer:

0.146 m/s

Explanation:

We can see it in the pic.

3 0

3 years ago

Two circular coils are concentric and lie in the same plane. The inner coil contains 170 turns of wire, has a radius of 0.0095 m

PIT_PIT [208]

Answer:

Current in outer circle will be 15.826 A

Explanation:

We have given number of turns in inner coil $N_I=170$

Radius of inner circle $r_i=0.0095m$

Current in the inner circle $I_i=8.9A$

Number of turns in outer circle $N_o=150$

Radius of outer circle $r_o=0.015m$

We have to find the current in outer circle so that net magnetic field will zero

For net magnetic field current must be in opposite direction as in inner circle

We know that magnetic field is given due to circular coil is given by

$B=\frac{N\mu _0I}{2r}$

For net magnetic field zero

$\frac{N_I\mu _0I_I}{2r_I}=\frac{N_O\mu _0I_0}{2r_O}$

So $\frac{170\times \mu _0\times 8.9}{2\times 0.0095}=\frac{150\times \mu _0I_O}{2\times 0.015}$

$I_O=15.92A$

4 0

3 years ago