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DENIUS [597]
2 years ago
12

Rebecca jogs in place for two minutes before her track meet. Rebecca weighs 100 pounds. Which of the following statements is tru

e?
A Rebecca has done 200 foot-pounds of work.
B Rebecca has not done work because she has not moved a distance.
C Rebecca would accelerate more quickly is she weighed 120 pounds.
D Rebecca has done 100 foot-pounds of work.
Physics
2 answers:
MrRissso [65]2 years ago
7 0
The answer is A because it was 2 minutes and she weighs 100 lbs.... so 2(100)=200.... 200 lbs of work
Nataly_w [17]2 years ago
7 0

Answer:

B. Rebecca has not done work because she has not moved a distance.

Explanation:

In physics, work represents the amount of energy necessary for a force to move a body a certain distance.

W=F.d, where <em>F</em> is the force, <em>d</em> the distance and <em>W</em> the work of the force <em>F.</em>

Since Rebecca jogs in place, the distance is zero, an so does the work.

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Two containers (A and B) are in thermal contact with an environment at temperature T = 280 K. The two containers are connected b
zmey [24]

Answer:

The maximum amount of work is  W = 1563.289 \ J

Explanation:

From  the question we are told that

   The temperature of the environment is  T = 280\ K

    The volume of container A is  V_A = 2 m^3

    Initially the number of moles  is  n = 1.2 \ moles

     The volume of container B is V_B = 3.5 \ m^3

     

At equilibrium of the gas the maximum work that can be done on the turbine is mathematically represented as

             W =  P_A V_A  ln[ \frac{V_B}{V_A} ]

Now from the Ideal gas law

          P_A V_A =  nRT

So substituting for P_A V_A in the equation above

          W =  nRT ln [\frac{V_B}{V_A} ]

Where R is the gas constant with a values of  R =  8.314 \  J/mol

Substituting values we have that

            W = 1.2 * (8.314) * (280) * ln [\frac{3.5}{2} ]

          W = 1563.289 \ J

8 0
3 years ago
A fish scale, consisting of a spring with spring constant k=200N/m, is hung vertically from the ceiling. A 2.6 kg fish is attach
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Answer:

Explanation:

The fish is initially at rest and it is also at rest when the spring is fully stretched at the maximum distance.

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100h^2 - 26h = 0

2h(50h - 13) = 0

h = 0 or h = 13/50 = 0.65m

h = 0 is before the spring is stretched

So the maximum distance is 0.65m.

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