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artcher [175]
3 years ago
11

The ------------- the temperature of an object, the faster the molecules vibrate.

Chemistry
2 answers:
pantera1 [17]3 years ago
6 0
The answer is higher
labwork [276]3 years ago
3 0
Higher, they have more energy so they move faster
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Select the options that are properties of electromagnetic waves:
kaheart [24]

Answer:

They propagate in materialistic media and non-materialistic media ( space ) .

They propagate in the space at constant velocity , which is 3 × 108 m/s .

They consist of vibrating electric and magnetic fields at certain frequency in phase with each other , perpendicular to each other and perpendicular to the direction of the wave propagation ...

Explanation:

welcome!

4 0
3 years ago
When a 0. 1 m aqueous solution of hydrocyanic acid, hcn, reaches equilibrium, the ph is measured to be 5. 20. using this informa
Sav [38]

When a 0. 1 m aqueous solution of hydrocyanic acid, HCN, reaches equilibrium, the ka for hydrocyanic acid is  3.969 x 10⁻¹⁰.

<h3>What is ka value?</h3>

It's the value of equilibrium constant for the dissociation of ions into a solution. The more the Ka value the more will be dissociation.

Ka = [H₃O⁺]² / [HCN] [H₃O⁺]

The pH is 5.20

-log [H₃O⁺] = 5.20

Putting antitlog both side.

The value will be 6.30 x 10⁻⁶

Ka = (6.30 x 10⁻⁶)²  / 0.1 - 6.30 x 10⁻⁶

0.1 - 6.30 x 10⁻⁶ = 0.1

Ka = 3.969 x 10⁻¹⁰

Thus, the Ka value for hydrocyanic acid is 3.969 x 10⁻¹⁰.

To learn more about ka value, refer to the link:

brainly.com/question/2796803

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7 0
1 year ago
Energy levels tell us how many _______ there are in an atom. ​
steposvetlana [31]

Answer:

Energy levels tell us how many <u>electrons </u>there are in an atom. ​

Hope this helps!

8 0
3 years ago
A key step in the extraction of iron from its ore isFeO(s) + CO(g) ⇄ Fe(s) + CO₂(g) Kp = 0.403 at 1000°CThis step occurs in the
Kisachek [45]

A key step in the extraction of iron from its ore isFeO(s) + CO(g) ⇄ Fe(s) + CO₂(g) Kp = 0.403 at 1000°CThis step occurs in the 700°C to 1200°C zone within a blast furnace. the partial pressure of CO2 at equilibrium is 1.58 atm.

The complete reaction of the problem, for better illustration, is

FeO(s) + CO(g) <--> Fe(s) + CO2(g)

The double-tailed arrow signifies that the reaction is in a dynamic chemical equilibrium. When the system is in equilibrium, the forward and the backward reaction rates have an equal ratio of Kp = 0.403 at 1000°C. The formula for Kp is

Kp = [partial pressure of products]/[partial pressure of reactants]

So, first, let's find the partial pressure of the compounds in the reaction.

                     FeO(s) + CO(g) <--> Fe(s) + CO2(g)

Initial                 x            1.58            0           0

Change           -1.58        -1.58       +1.58     +1.58

------------------------------------------------------------------

Equilbrium      x-1.58          0             1.58       1.58

Kp = [(1.58)(1.58)]/[(x-1.58)] = 0.403

x = 7.77 atm (this is the amount of excess FeO)

Therefore, the partial pressure of CO2 at equilibrium is 1.58 atm. There is no more CO because it has been consumed due to excess FeO.

To know more about partial pressure of CO2 at equilibrium

brainly.com/question/16022760

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6 0
2 years ago
What is the mass in grams of 394 mL of ethylene glycol? Express your answer with the appropriate units.
AleksandrR [38]

Answer : The mass of ethylene glycol is, 437.34 grams

Solution : Given,

Volume of ethylene glycol = 394 ml

Density of ethylene glycol = 1.11 g/ml    (Standard value)

Formula used :

Density=\frac{Mass}{Volume}

Now put all the given values in this formula, we get the mass of ethylene glycol.

1.11g/ml=\frac{Mass}{394ml}

Mass=437.34g

Therefore, the mass of ethylene glycol is, 437.34 grams

3 0
3 years ago
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