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Novay_Z [31]
3 years ago
8

What are the coefficients to balance the following equation? ba+br2=babr2

Chemistry
2 answers:
Sphinxa [80]3 years ago
7 0
This one’s already balanced.

1 ba on each side. 2 br on each side. Coefficient for all of them is 1.
kaheart [24]3 years ago
6 0

Answer:

Its already balanced

Explanation:

Ba (barium) starts with and ends with 1. Br (bromine) starts with 2 and ends with 2.

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Which organelle allows plants to make their own food?
Setler [38]

Answer:

chloroplast is the correct answer

5 0
3 years ago
Billions of pounds of urea are produced annually for use as a fertilizer. Balance the skeletal equation for the synthesis of ure
klio [65]
2NH₃(g) + CO₂(g) → CO(NH₂)₂(s) + H₂O(l)
is the balanced equation for the synthesis of urea.
5 0
3 years ago
Which mass of urea, CO(NH2)2, contains the same mass of nitrogen as 101.1g of potassium nitrate?
Effectus [21]
In order to calculate the mass of nitrogen, we must first calculate the mass percentage of nitrogen in potassium nitrate. This is:
% nitrogen = mass of nitrogen / mass of potassium nitrate
% nitrogen = 14 / 101.1 x 100

The mass of nitrogen = % nitrogen x sample mass
= (14 / 101.1) x 101.1
= 14 grams

The molar weight of nitrogen is 14. Each mole of urea contains two moles of nitrogen. Therefore, for there to be 14 grams of nitrogen, there must be 0.5 moles of urea.
Mass of urea = moles urea x molecular weight urea
Mass of urea = 0.5 x 66.06
Mass of urea = 33.03 grams
4 0
3 years ago
What does the number 7 mean in the following example-73Li?
Pavlova-9 [17]

Answer:

7 is the mass number of li and 3 is the atomic number

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c 3

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4 0
2 years ago
A 25.0 mL aliquot of 0.0680 M EDTA was added to a 59.0 mL solution containing an unknown concentration of V3 . All of the V3 pre
givi [52]

Answer:

\mathbf{0.02 M}

Explanation:

\text{So, from the given question:}

\text{EDTA will make complex with} V^{+3} \text{and the remaining EDTA will react with }Ga^{+3}

\text{Hence, the total concentration of} V^{+3} & Ga^{+3} \text{will be equivalent to EDTA concentration.}

V_{EDTA} = 25 \ mL

V_{V^{+3}} = 59.0 \ mL

V_{Ga^{+3}} = 13.0 \ mL

M_{EDTA} = 0.0680 \ M

M_{V^{+3}} = ???(unknown)

M_{Ga^{+3}} = 0.0400 \ M

V^{+3} + EDTA \to V[EDTA] + EDTA(Excess)  \to^{CoA} \ Ga[EDTA] _{complex}

M_{EDTA} \times V_{EDTA} = ( V_{V^+3}\times M_{V^{+3}}+ V_{Ga^{+3} }\times M_{Ga^{+3}}})

0.0680 \times 25 = (59\times x + 13 \times 0.040) \\ \\ 1.7 = 59x + 0.52\\ \\ 1.7 - 0.52 = 59x \\ \\ 59x = 1.18

x = \dfrac{1.18}{59}

\mathbf{x =0.02 \ M }

5 0
3 years ago
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