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guajiro [1.7K]
3 years ago
8

When a space shuttle was launched, the astronauts onboard experienced an acceleration of 32.0 m/s2 . If one of the astronauts ha

d a mass of 40.0 kg, what net force in newtons did the astronaut experience?
Physics
1 answer:
jarptica [38.1K]3 years ago
8 0

Answer:

F = 1280 N

Explanation:

Given that,

Acceleration experienced by a space shuttle, a = 32 m/s²

Mass of the astronauts, m = 40 kg

We need to find the force experienced by the astronaut.

We know that the net force is equal to the product of acceleration and its mass. So,

F = ma

F = 40 kg × 32 m/s²

So,

F = 1280 N

So, 1280 N of force is experienced by the Astronaut.

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69.2 m with a velocity of 1.40* 10^2 km/h.

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A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during
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The acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².

The given parameters;

  • <em>initial velocity of the engine, u = 1341 m/s</em>
  • <em>final velocity of the engine, v = 7600 m/s</em>
  • <em>time of motion, t = 2 minutes = 2 x 60 s = 120 s</em>

The acceleration of the SRB and main engine is calculated as follows;

a = \frac{\Delta v}{\Delta t } \\\\a = \frac{7600 - 1341}{2 \times 60  s} \\\\a = 52.16 \ m/s^2

Thus, the acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².

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3 years ago
A cylinder of gas at room temperature has a pressure . To p_{1} what temperature in degrees Celsius would the temperature have t
grandymaker [24]

In order to calculate the temperature, we need to know that temperature and pressure are directly proportional, that is, if the pressure increases, the temperature (in Kelvin) also increases in the same proportion.

So, first let's convert the temperature from Celsius to Kelvin, by adding 273 units:

\begin{gathered} K=C+273 \\ K=20+273 \\ K=293 \end{gathered}

Then, let's calculate the proportion:

\begin{gathered} \frac{P_1}{T_1}=\frac{P_2}{T_2} \\ \frac{p_1}{293}=\frac{1.5p_1}{T_2} \\ \frac{1}{293}=\frac{1.5}{T_2} \\ T_2=1.5\cdot293 \\ T_2=439.5\text{ K} \end{gathered}

Now, converting back to Celsius, we have:

\begin{gathered} C=K-273 \\ C=439.5-273 \\ C=166.5\text{ \degree{}C} \end{gathered}

So the temperature would be 166.5 °C.

6 0
1 year ago
A discus thrower turns with angular acceleration of 50 rad/s2, moving the discus in a circle of radius 0.80m. Find the radial an
anyanavicka [17]

Answer:

The value of tangential acceleration \alpha_{t} =  40 \frac{m}{s^{2} }

The value of radial acceleration \alpha_{r} = 80 \frac{m}{s^{2} }

Explanation:

Angular acceleration = 50 \frac{rad}{s^{2} }

Radius of the disk = 0.8 m

Angular velocity = 10 \frac{rad}{s}

We know that tangential acceleration is given by the formula \alpha_{t} = r \alpha

Where r =  radius of the disk

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⇒ \alpha_{t} = 0.8 × 50

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This is the value of tangential acceleration.

Radial acceleration is given by

\alpha_{r} = \frac{V^{2} }{r}

Where V = velocity of the disk = r \omega

⇒ V = 0.8 × 10

⇒ V = 8 \frac{m}{s}

Radial acceleration

\alpha_{r} = \frac{8^{2} }{0.8}

\alpha_{r} = 80 \frac{m}{s^{2} }

This is the value of radial acceleration.

7 0
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zzz [600]

Explanation:

This question is not feasible. There is no way to calculate the energy needed because the question is missing the final temperature

7 0
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