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SOVA2 [1]
3 years ago
7

These mixed messages be impossable

Chemistry
2 answers:
lara [203]3 years ago
7 0
What...
Thanks for the points
Hitman42 [59]3 years ago
6 0

Answer:

What?

Explanation:

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How many sulfur atoms are in 0.45 mol BaSO4??
Lemur [1.5K]

(0.45 mol BaSO_{4})*(\frac{6.022*10^23 molecules}{mol})*(\frac{1 atom S}{1 molecule BaSO_{4}}) = 2.7*10^{23}

4 0
3 years ago
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Define the term valence electron and explain how to find the number of valence electrons in family one and family 2.
goblinko [34]
Valence Electron is the outermost electrons, family(Alkali) 1 has 1 valence electrons and family(Alkaline) 2 has 2 valence electrons.

Hope this helps
8 0
3 years ago
Need help fast please 15 points!!!
In-s [12.5K]

Answer:

C. disposition and condensation ​

Explanation:

8 0
3 years ago
A 10 gram sample of iron reacts with oxygen to form 18.2 grams of ferric oxide. How many grams of oxygen reacted?
RoseWind [281]

Answer:

\boxed {\boxed {\sf 8.2 \ grams}}

Explanation:

According to the Law of Conservation of Mass, the mass of the products must equal the mass of the reactants.

  • mass products = mass reactants

In this problem, the reaction is:

iron + oxygen = ferric \ oxygen

  • The reactants are iron and oxygen. We know the mass of the iron sample is 10 grams.
  • The product is ferric oxide. The mass of the ferric oxide sample is 18.2 grams.

10 \ g + oxygen=18.2 \ g

We want to find how many grams of oxygen reacted. We have to get the oxygen by itself. 10 is being added to oxygen. The inverse of addition is subtraction. Subtract 10 from both sides of the equation.

10 \ g - 10 \ g+ oxygen = 18.2 \ g - 10 \ g

oxygen= 18.2 \ g - 10 \ g

oxygen= 8.2 \ g \\

<u>8.2 grams of oxygen </u>reacted with 10 grams of iron to form 18.2 grams of ferric oxide.

8 0
3 years ago
Suggest a method for measuring the size of the colony.
Evgen [1.6K]

Answer:

Counting the number of colonies that arise on a pour plate can calculate the concentration by multiplying the count by the volume spread on the pour plate. Direct counting methods are easy to perform and do not require highly specialized equipment, but are often slower than other methods

Explanation:

I hope it will help you

7 0
3 years ago
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