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Licemer1 [7]
3 years ago
6

Which is a cause of polarity in water molecules?

Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
8 0

Answer:

an uneven charge between the oxygen molecule and 2 hydrogen molecules

Explanation:

bogdanovich [222]3 years ago
5 0
High electronegativity difference between oxygen and hydrogen
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Which statements correctly describe thermal energy in a block of ice, a glass of liquid water, and a container of steam?
DanielleElmas [232]

Answer:

Steam always has more thermal energy than ice.

Explanation:

6 0
3 years ago
If oxygen is removed from a sample of air as iron nusts, what happens to the partial pressure of oxygen in the air?
trasher [3.6K]

Answer:

It increases because the less oxygen the more pressure there will be on that specific object

Explanation:

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3 years ago
How many moles are in a 62.5-g sample of potassium nitrate (KNO3)?
Reil [10]

Answer:25.3 g of KNO₃ contain 0.25 moles.

Explanation:

7 0
3 years ago
19. If it takes more energy to break the bonds of the reactants than is released when the bonds of
frozen [14]

Answer:

If it takes more energy to break the original bonds than is released when the new bonds are formed, then the net energy of the reaction is negative. This means that energy must be pumped into the system to keep the reaction going. Such reactions are known as endothermic.

Explanation:

5 0
3 years ago
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
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