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vazorg [7]
3 years ago
8

What is the coefficient for hydrogen in the balanced equation for the reaction of solid molybdenum(iv) oxide with gaseous hydrog

en to form solid molybdenum and liquid water?
Chemistry
1 answer:
anastassius [24]3 years ago
3 0

The  coefficient  for hydrogen  in  the  balanced  equation   of solid  molybdenum(iV)  oxide  with gaseous  hydrogen  is  2


 Explanation

Coefficient   is defined  to  as  a number  in front   of a chemical formula in a  balanced chemical equation.

   The  reaction   of   molybdenum (iv) oxide  with  gaseous  hydrogen  is  as below,


MoO2  + 2 H2→  Mo  +2 H2O

From   balanced equation above  the coefficient   for  H2  is  2  since  the number in  front of  H2  is 2



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Select the correct electron configuration for Boron. (Atomic Number 5) 1s 22s 12p 2 1s 22s 3 1s 32s 12p 1 1s 22s 22p 1
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In a simple distillation setup, what is the sequence of equipment from the bench top to the round bottom flask
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In a simple distillation setup, the sequence of equipment from the bench top to the round bottom flask is:

  • Thermometer
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<h3>What is Distillation?</h3>

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3 0
2 years ago
Consider the redox reaction below.
vovangra [49]

Answer:

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Explanation:

Let us consider the complete redox reaction:

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

This is a redox reaction because, both oxidation and reduction is simultaneously taking place.

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Here Zn(s) is undergoing oxidation from OS 0 to +2

And H in HCl (aq) is undergoing reduction from OS +1 to 0.

Therefore, for this reaction;

Oxidation Half equation is:

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4 0
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Answer:

7 moles

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8 0
3 years ago
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