3 years ago

What is the approximate radius of a nitrogen nucleus that has seven protons and seven neutrons?

Physics

1 answer:

mrs_skeptik [129]3 years ago

7 0

Answer:

3.5E-15m

Explanation:

Using

R= Ro A^ 1/3

Where Ro= 1.2fm

and A= 7

= 1.2*10^-15 x (7)^1/3

= 3.5*10^-15m

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dimulka [17.4K]

=1244 and that's from my math book

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3 years ago

The force of attraction between a -165.0 uC and +115.0 C charge is 6.00 N. What is the separation between these two charges in m

Molodets [167]

Answer:

r = 5.335 meters

Explanation:

Given that,

Charge 1, $q_1=-165\ \mu C$

Charge 2, $q_2=115\ \mu C$

Force of attraction between two charges, F = 6 N

The force of attraction between two charges is given by :

$F=k\dfrac{q_1q_2}{r^2}$ , r is the separation between two charges

$r=\sqrt{\dfrac{kq_1q_2}{F}}$

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r = 5.335 m

So, the separation between two charges is 5.335 meters. Hence, this is the required solution.

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3 years ago

Your ear is capable of differentiating sounds that arrive at the ear just 1.00 ms apart. What is the minimum distance (in cm) be

kenny6666 [7]

Answer:

34.3cm

Explanation:

Attached is the full solution

8 0

4 years ago

A charge of 6.7 x 10 coulombs is located at a point where its potential energy is 5.6 x 10-12 joules. What is the electric poten

Georgia [21]

6.7 X 10 = 670

5.6 X 10 - 12 =44

714

5 0

3 years ago

In a certain experiment, cylindrical samples of diameter 4 cm and length 7 cm are used. The two thermocouples in each sample are

sergeinik [125]

Answer:

K = .3941 × 10³ W/m.K

Explanation:

Qcond = K A ΔT÷ L

∴K = Qcond ×L ÷ A ΔT

J ÷ S = P

P = I × V =Qcond

∴Qcond = I × V

= 0.6 A × 110 V

=66 W

L = 0.12 m

ΔT = 8 °C

Qcond =33 V

Area = (πD²) ÷ 4

= [π (4 × 10⁻² )²] ÷ 4

= 1.256 × 10⁻³ m²

∴A = 1.256 × 10 ⁻³³ m²

So K = ( Qcond × L ) ÷ A ΔT

= (33) (0.12 ) ÷ (1.256 ×10⁻³ ) × 8

= 0.3941 × 10³ W/m .K

7 0

3 years ago