Question #1:
That's an description of an <em>parallel</em> circuit. <em>(b)</em>
Question #2:
Power = (current) x (voltage)
Power = (0.4 A) x (120 v)
Power = <em>48 watts</em>
Incomplete question as many data is missing.I have assumed value of charge and electric field.The complete question is here
A charge of 28 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 5.00×10⁴ V/m.
What work is done by the electric force when the charge moves a distance of 2.70 m at an angle of 45.0 degrees downward from the horizontal?
Answer:
Explanation:
Given data
Charge q=28 nC
Electric field E=5.00×10⁴ V/m.
Distance d=2.70 m
Angle α=45°
To find
Work done by electric force
Solution
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Answer:
In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero,
Explanation:
When a satellite is in orbit the most important force is the docking of gravity with the Earth
F = m a
where the acceleration is centripetal and F is the force of universal attraction
centripetal acceleration is
a = v² / r
F = m v² / r
In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero, the force also drops to serious and the satellite steels to Earth.
The speed of the satellite is provides the speed, by local for smaller speeds in satellite, it descends in its orbits and when the speed is amate you have the energy to stop an orb to go to a higher orbit.
Explanation:
700N right
to get the net force
you gotta let one direction be the negative ( the smaller force)
so the total force towards the left is 100N ( 60 + 40= 100)
which is smaller than the right force which is 800 N so you let 100 N be negative
so without even calculating , you can know that it will be moving towards the right because right force > left force
your add both forces ( remember 100 N is negative)
so 800N + ( - 100N)
= 700N
towards the right
hope this helps
this is just one method that helped me understand
please mark it brainliest
