The magnitude of the force of friction is 40 N
Explanation:
To solve the problem, we just have to analyze the forces acting on the student and the scooter along the horizontal direction. We have:
- The constant pushing force forward, of magnitude F = 40 N
- The frictional force, acting backward, 
Since the two forces are in opposite direction, the equation of motion is

where
m is the mass of the student+scooter
a is the acceleration
However, here the scooter is moving at constant speed: this means that its acceleration is zero, so
a = 0
And therefore,

which means that the magnitude of the force of friction is also equal to 40 N.
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Answer:
A) 
B) 
C) 
Explanation:
Given:
- mass of flywheel,

- diameter of flywheel,

- rotational speed of flywheel,

- duration for which the power is off,

- no. of revolutions made during the power is off,

<u>Using equation of motion:</u>



Negative sign denotes deceleration.
A)
Now using the equation:


is the angular velocity of the flywheel when the power comes back.
B)
Here:

Now using the equation:


is the time after which the flywheel stops.
C)
Using the equation of motion:


revolutions are made before stopping.
D. Jupiter has the highest amount of gravity in our solar system
Answer:
The wavelength of these signals is as follow:
- Wavelength of 550 kHz is 545.45 m
- Wavelength of 1600 kHz is 187.5 m
Explanation:
Given that:
Frequency = 550 kHz & 1600 kHz
Velocity = 3.0 x 10⁸ m/s
As we know that frequency is expressed by the following equation:
- Frequency = Velocity / Wavelength ---- (1)
For 550 kHz:
The equation can be rearranged as
Wavelength = Velocity / Frequency
Wavelength = (3.0 x 10⁸ m/s) / (550 x 1000 Hz)
Wavelength = 545.45 m
For 1600 kHz:
Wavelength = Velocity / Frequency
Wavelength = (3.0 x 10⁸ m/s) / (1600 x 1000 Hz)
Wavelength = 187.5 m
Answer:
1) 0.43 meters per second
2) 0.21 meters per second
3) 1.02 
4) 0.66 seconds
Explanation:
part 1
By conservation of energy, the maximum kinetic energy (K) of the block is at equilibrium point where the potential energy is zero. So, at the equilibrium kinetic energy is equal to maximum potential energy (U):


With m the mass, v the speed, k the spring constant and xmax the maximum position respect equilibrium position. Solving for v

part 2
Again by conservation of energy we have kinetic energy equal potential energy:


part 3
Acceleration can be find using Newton's second law:

with F the force, m the mass and a the acceleration, but elastic force is -kx, so:


part 4
The period of an oscillator is the time it takes going from one extreme to the other one, that is going form 4.5 cm to -4.5 cm respect the equilibrium position. That period is:

So between 0 and 4.5 cm we have half a period:
